Answer:
The electric force will be 0 N
Explanation:
From the question we are told that
The magnitude of the charge is 
Generally from Coulombs law the electric force between two charges is mathematically represented as

Here r is the distance of separation between that two charges.
Now from the question we are told that the charge is far away from any other charge hence we can say that the distance between the charge and any other charge is 
So

=> 
Hence the electric force will be 0 N