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Lerok [7]
3 years ago
15

5. A belt runs on a wheel of 30.0-cm radius. During the time that the wheel coasts uniformly to rest from an initial speed of 2.

00 rev/s, 25.0 m of belt length passes over the wheel. Find the angular acceleration of the wheel and the total number of revolutions it turns before stopping.

Physics
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer:

Angular acceleration = 0.95rad/s

Number or revolution is 13

Explanation:

See attached file

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2 Select the correct answer. Javed suffers from a severe food allergy. Which device should Javed always carry? A. inhaler B. epi
Slav-nsk [51]

The best answer would be:

B. Epi pen

Here is more about it:

An epi pen injects epinephrine into the body to counteract the effects of an allergic reaction. Epinephrine helps narrow blood vessels and open up the airways. This can be used for food allergies, insect bites, and some other allergens. It is very effective and immediately works, but it is short-lived, so seeking medical attention after is still needed.

4 0
3 years ago
A kangaroo jumps up with an initial velocity of 36 feet persecond from the ground (assume its starting height is 0 feet).Use the
kkurt [141]

Given

Initial velocity:

36 ft/s

Initial height:

0 ft

Vertical motion model:

h(t) = -16t^2 + ut + s

v = initial velocity

s = is the height

Procedure

We are going to use the model provided for the vertical motion.

\begin{gathered} h(t)=-16t^2+36t+0 \\ h(t)=-16t^2+36t \end{gathered}

We know that at the maximum height the final velocity is 0.

Then we will use the following expression to calculate the maximum height:

\begin{gathered} v^2_f=v^2_o-2ah_{\max } \\ 0=v^2_o-2ah_{\max } \\ 2ah_{\max }=v^2_o \\ h_{\max }=\frac{v^2_o}{2a} \\ h_{\max }=\frac{(36ft/s)^2}{2\cdot32ft/s^2} \\ h_{\max }=20.25\text{ ft} \end{gathered}

Now for time:

\begin{gathered} 20.25=-16t^2+36t \\ 16t^2-36t+20.25=0 \end{gathered}

Solving for t,

\begin{gathered} t_1=2.25 \\ t_2=0 \end{gathered}

The total time the kangaroo takes in the air is 2.3s.

3 0
1 year ago
In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
Murljashka [212]

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

final speed of the box, v = 10 m/s

Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

¹/₂ x 8 x 10² = Ux

400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

8 0
3 years ago
Which part of john dalton’s theory was disproved by j. J. Thomson’s cathode-ray tube experiments?.
Leni [432]

Answer:

While controversial at first, Thomson's discoveries were gradually accepted by scientists. Eventually, his cathode ray particles were given a more familiar name: electrons. The discovery of <em>the electron</em> disproved the part of Dalton's atomic theory that assumed atoms were indivisible.

5 0
3 years ago
A battery is connected to the two ends of a conducting rod and the current through it is measured.a) Another rod, made of the sa
IceJOKER [234]

Answer:

a) - the resistance is proportional to the length of the metal

   - a thicker rod, since resistance decreases with increasing area

b)  The current is proportional to the area so this is the factor that is influenced by the electric field  

Explanation:

a) When the rod is connected to the rod an electrical circuit described by the expression is formed

          V = I R

          I = V / R

The resistance of the rod is

         R = ρ L / A

Where ρ is the resistivity of metal, L Longitud and A cross section.

If a higher current is measured when the other rod is connected, it implies that the resistance has decreased. To have a decrease in resistance you have two possibilities

- use a shorter rod, since the resistance is proportional to the length of the metal

- Use a thicker rod, since resistance decreases with increasing area, remember that the area of ​​a circle is

                  A = π R²

Therefore, small increases in the diameter of the rod could give great changes in resistance.

b) The current is defined with the charge that crosses a surface per unit of time, when the electric field increases the electrons feel a greater force, therefore the current increases.

The charge number on a wire is

              Q = q n v_{d} Δt A

So up to date is

               I = q n When the rod is connected to the rod an electrical circuit described by the expression is formed

          V = I R

          I = V / R

The resistance of the rod is

         R = rho L / A

Where rho is the resistivity of metal, L e; Long and A cross section.

If a higher current is measured when the other rod is connected, it implies that the resistance has decreased. To have a decrease in resistance you have two possibilities

.- use a shorter rod, since the resistance is proportional to the length of the metal

. - Use a thicker rod, since resistance decreases with increasing area, remember that the area of ​​a circle is

                  A = pi R2

Therefore, small increases in the diameter of the rod could give great changes in resistance.

.b) The current is defined with the charge that crosses a surface per unit of time, when the electric field increases the electrons feel a greater force, therefore the current increases.

The load number on a wire is

              Q = q n v_{d} Dt A

So  current  is

               I = q n v_{d} A

The drag speed (v_{d}) is constant in the materials, it depends on the purity and imperfections, so a change in the length does not significantly change the current.

  The current is proportional to the area so this is the factor that is influenced by the electric field  

The drag speed (vd) is constant in the materials, it depends on the purity and imperfections, so a change in the length does not significantly change the current.

  The current is proportional to the area so this is the factor that is influenced by the electric field

8 0
3 years ago
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