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3 years ago

How would you factor a quadratic expression like 9x^2-4

Mathematics

1 answer:

Ganezh [65]3 years ago

7 0

Hello, we need to see it as a difference of two squares as we know that for all a and b real numbers

$a^2-b^2=(a-b)(a+b)$

So, here

$9x^2-4=(3x)^2-2^2=(3x-2)(3x+2)$

Voila !

Thank you

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Please help! I attached the question below.

kompoz [17]

Answer:

$\frac{2(c+2)}{c(c-2)}$

Step-by-step explanation:

$\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }$

Identity used:

$a^{2}-b^{2}=(a-b)(a+b)$

$\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }$

Now let us divide the modified expressions:

$\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})}$ ÷ $\frac{(c-2)^2}{2(6c^{3}+15c^{2}) }$

we get:

$\frac{2(c+2)}{c(c-2)}$

5 0

3 years ago

PLEASE HELP!!

professor190 [17]

Answer:

The answer is 33.2*F (72.3*F - 39.1*F because the temp. is *dropping* 39.1*F)

Step-by-step explanation:

If there is a negative change in temp. then that is just like subtracting the change from the base degree (F)

7 0

3 years ago

Read 2 more answers

What is that product of 2x + y and 5x -y + 3

poizon [28]

Answer:

10x² + 6x + 3xy + 3y - y²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, as shown

(2x + y)(5x - y + 3)

= 2x(5x - y + 3) + y(5x - y + 3) ← distributing

= 10x² - 2xy + 6x + 5xy - y² + 3y ( collect like terms )

= 10x² + 6x + 3xy + 3y - y²

7 0

3 years ago

Read 2 more answers

Pls someone answer pls :)

Goshia [24]

Answer:

(-x-2) (-2x -3)=0

=>[-(x +2)] [-(2x+3)]=0

=>(x + 2)(2x +3)=0

=>x =-2 or,x=-3/2

smaller x=-2

larger x =-3/2

3 0

3 years ago

Read 2 more answers

help thanks for taking the time to help

I am Lyosha [343]

Answer:

Con esto te sacas 10

2.5 cm

4 0

3 years ago