2 years ago

How would you factor a quadratic expression like 9x^2-4

Mathematics

1 answer:

Ganezh [65]2 years ago

7 0

Hello, we need to see it as a difference of two squares as we know that for all a and b real numbers

$a^2-b^2=(a-b)(a+b)$

So, here

$9x^2-4=(3x)^2-2^2=(3x-2)(3x+2)$

Voila !

Thank you

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The value of y varies directly with x and y = 4.5 when x = 0.5. find y when x = 10

Pepsi [2]

So what you asked this is what I got

x(y) = 4.5

If x= 0.5 then

0.5(y) = 4.5
y=9

x(y) = 4.5

10(y) = 4.5
y= 0.45

hope this helps :)

3 0

2 years ago

Find the slope between these two points: (3, -10) and (-2, -30). Show all of your work. what the answer

Harlamova29_29 [7]

$\huge\text{$m=\boxed{4}$}$

Hey there! Start with the slope formula, where $(x_1,y_1)$ and $(x_2,y_2)$ are the two known points.

$\begin{aligned}m&=\dfrac{y_2-y_1}{x_2-x_1}\\&=\frac{-30-(-10)}{-2-3}\end{aligned}$

Simplify.

$\begin{array}{c|l}\textbf{Solving}&\textbf{Reason}\\\cline{1-2}\\m=\dfrac{-30+10}{-2-3}&x-(-y)=x+y\\\\m=\dfrac{-20}{-5}&\text{Addition and subtraction}\\\\m=\dfrac{20}{5}&\text{The negatives cancel out}\\\\m=\dfrac{4}{1}&\text{Divide the numerator and denominator by $5$}\\\\m=\boxed{4}&\dfrac{x}{1}=x\end{aligned}$