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3 years ago

Javier bought a baseball card for 75% of its original shoes how much Javier paid for the baseball card?

Mathematics

1 answer:

Alex Ar [27]3 years ago

7 0

3/4 X 10= $7.50

Because 3/4 is 75%, 10 is the original price. And 75% times 10 is 7.50

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What two numbers multiply to 6 but add up to -1?

Artyom0805 [142]

Answer:

-3 and 2

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

You split $1500 between two savings accounts one pays 4%interest and the other pays 5% after one year you have earned $69.50 in

ANTONII [103]

Answer:

Step-by-step explanation:

Use the basic simple interest formula:

P * r * t = I and put the info into a table with those variables along the top, formig the columns we need:

P * r * t = I

Acct 1

Acct 2

If we have a total of 1500 to split up between 2 accounts, we put x amount of money into one and then have 1500-x left to put into the other. We will fill those in along with the interest rates in decimal form and the time of 1 year:

P * r * t = I

Acct 1 x .04 1

Acct 2 1500-x .05 1

Looking at the formula we are told that Prt = I, so we will multiply P times r times t and fill in the I column:

P * r * t - I

Acct 1 x .04 1 .04x

Acct 2 1500-x .05 1 .05(1500-x)

The total Interest earned by the addition of the interest earned from both accounts is 69.50. So we add the interest column together and set it equal to 69.50:

.04x + .05(1500 - x) = 69.50 and

.04x + 75 - .05x = 69.50 and

-.01x = -5.5 so

x = 550

That's how much money is in the account earning 4% interest.

7 0

2 years ago

How do I solve this?

krok68 [10]

3 is 95 and 4 is 85. I believe

4 0

2 years ago

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$