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choli [55]
3 years ago
7

Which of the following molecules is formed by single bonds alone?

Chemistry
1 answer:
IgorLugansk [536]3 years ago
4 0

Answer:

The F₂ molecule is formed by single bonds alone.

Explanation:

The octate rule dictates that atoms have a preference to have 8 electrons in their valence shells. Considering this rule we can analyse how the electrons are distributed in the molecules and see how the atoms bond to obbey the rule.

The fluorine atom has 7 electrons in its valence shell. This means that it needs one more electron to reach stability. Therefore, when two fluorine atoms combine, they share one electron each, forming a single bond.

The atoms of the other molecules need more than one electron to reach the octate, therefore they need to share more electrons, forming double and triple bonds.

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If air has a dry-bulb temperature of 2°C
Allisa [31]

Answer:

The relative humidity is 36%.

Explanation:

Relative humidity is the measure of ratio of actual vapor density to saturated vapor density in a given system. So there are different ways to measure the relative humidity in the atmosphere. One of the common ways is to measure using Psychrometer. In this instrument, two different thermometers are used as measuring device. One of the thermometer measures the humidity in dry air and another in wet air. So the difference of the temperature of dry and wet air bulb will be related to determine the relative humidity percentage. The formula to determine the relative humidity using this method is as below.

Relative humidity=\frac{(e_{w}-[N*(1+0.00115*T_{w}*(T_{d}-T_{w}))])*100}{e_{d} }

Also,

e_{d}=6.112*e^{[\frac{(17.502*T_{d} )}{(240.97+T_{d} )}]}

And,

e_{w}=6.112*e^{[\frac{(17.502*T_{w} )}{(240.97+T_{w} )}]}

Here e =2.718, T_{d} and T_{w} are the temperature at dry bulb and wet bulb temperatures, respectively.

So, the relative humidity after substituting the values of Td = 2 C and Tw = -2 C is 36%.

6 0
3 years ago
What are mixtures that have evenly mixed groups of particles that do not settle out called?
Alisiya [41]
Homogeneous mixtures.
Hope this helps.
7 0
3 years ago
A compound consisting of b, n, and h undergoes elemental analysis. the % composition by mass is found to be 40.28% b, 52.20% n,
svp [43]
To compute for the empirical formula, assume there is 100 grams of the compound. That means there is 40.28 g B, 52.2 g N and 7.53 g H. Convert the mass into moles using their molar masses:

40.28 g B * 1 mol/10.811 g = 3.725835 mol B
52.2 g N * 1 mol/14 g = 3.72857 mol N
7.53 g H * 1 mol/1 g = 7.53 mol H

Divide all the moles by the smallest amount which is 3.725835 mol.

B: 3.725835/3.725835 = 1
N: 3.72857/3.725835 = 1
H: 7.53/3.725835 = 2

Therefore, the empirical formula is BNH₂.
8 0
3 years ago
The reaction N O space plus thin space O subscript 3 space rightwards arrow space N O subscript 2 space plus thin space O subscr
nikklg [1K]

Answer:

4.3 × 10⁻⁵ M s⁻¹

Explanation:

Step 1: Given data

  • Rate constant (k):  2.20 × 10⁷ M⁻¹s⁻¹
  • Concentration of NO ([NO]): 3.3 × 10⁻⁶ M
  • Concentration of O₃ ([O₃]): 5.9 × 10⁻⁷ M
  • First order with respect to both NO and O₃

Step 2: Write the balanced reaction

NO + O₃ ⇒ NO₂ + O₂

Step 3: Calculate the reaction rate

The rate law is:

rate = k × [NO] × [O₃]

rate = 2.20 × 10⁷ M⁻¹s⁻¹ × 3.3 × 10⁻⁶ M × 5.9 × 10⁻⁷ M

rate = 4.3 × 10⁻⁵ M s⁻¹

6 0
4 years ago
Senario: 2 years ago, a fruit was smuggled into California on a plane from an exotic, far away land. The homeowner saw that the
Umnica [9.8K]

Answer:

The best existing methods of control—artemisinin-based drug treatment and insect control with chemical sprays and treated bednets—can reduce the burden of disease substantially, and can even eliminate the disease in some regions,

hope this will help you more

4 0
3 years ago
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