Answer:
C. Infinitely Many Solutions
<u>Explanation:</u>
No solution case : This is the case when all given variables are not equal to any constant, for example: there is one row of zeros in matrix <em>e.g 0=3</em>. matrix B don't have any zero row. <u>So, Not True. </u>
One Solution case: This is the case when all variables are independent variables like if they are equal to some constant. <em>e.g x=1,y=2,z=4 </em>, Matrix B have more than one variable in first row due to which it made equation look like <em>x+y=-5. so matrix B can't have only one solution. </em><u>So, Not True.</u>
Infinitely Many Solutions case: when there is one or more variables which is not equal to any constant and acting as linearly dependent variable, then that matrix have infinite solutions. Matrix B have that variable which is linearly dependent as show in the attachment solution.<u> So, True. </u>
Answer:
<em> </em><em>T</em><em>he </em><em>main </em><em>universal </em><em>indicator</em><em> </em><em>is </em><em>in </em><em>the </em><em>form </em><em>of </em><em>a </em><em>solution</em><em> </em><em>and </em><em>are </em><em>thymol </em><em>blue </em><em>,</em><em> </em><em>methyl </em><em>red </em><em>,</em><em> </em><em>bromothymol </em><em>blue </em><em>and </em><em>phenolphthalein </em><em>this </em><em>mixture </em><em>is </em><em>important </em><em>because</em><em> </em><em>each </em><em>component </em><em>loses </em><em>or </em><em>gains </em><em>protons </em><em>depending</em><em> </em><em>upon </em><em>the </em><em>acidity </em><em>of </em><em>the </em><em>solution</em><em> </em><em>being</em><em> </em><em>tested </em><em>.</em>
<em><u>maybe </u></em><em><u>this </u></em><em><u>m</u></em><em><u>i</u></em><em><u>ghr </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em>
I and III because when wearer boil the kinetic energy atoms move faster and the particles break apart which means the space increases instead of decreasing
Genetic variation mean to gangbang!
% by mass = (mass solute/mass solution)*100%
mass of the solute = 54.7 g
mass of the solution = mass solute + mass solvent=54.7+500=554.7 g
% by mass = (54.7/554.7)*100%≈0.0986*100% = 9.86%