In △ABC, m∠A=72
°, c=61
, and m∠B=16
°. Find the perimeter of the triangle.
1 answer:
Answer:
perimeter of the triangle = 136
Step-by-step explanation:
∡A = 72 side a = ?
∡B = 16 side b = ?
∡C = 180 - 72 - 16 = 92 side c = 61
sinA/a = sinC/c
sin72/a = sin92/61
a = (sin72 * 61) / sin92
a = 58
sinA/a = sinB/b
sin72/58 = sin16/b
b = (sin16 * 58) / sin72
b = 17
perimeter = a + b + c
perimeter = 58 + 17 + 61
perimeter = 136
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