Question

In △ABC, m∠A=72 °, c=61 , and m∠B=16 °. Find the perimeter of the triangle.

Answer 1

Answer:

perimeter of the triangle = 136

Step-by-step explanation:

∡A = 72     side a = ?

∡B = 16      side b = ?

∡C = 180 - 72 - 16 = 92   side c = 61

sinA/a = sinC/c

sin72/a = sin92/61

a = (sin72 * 61) / sin92  

a = 58

sinA/a = sinB/b

sin72/58 = sin16/b

b = (sin16 * 58) / sin72

b = 17

perimeter = a + b + c

perimeter = 58 + 17 + 61

perimeter = 136