A) initial volume
We can calculate the initial volume of the gas by using the ideal gas law:
where
is the initial pressure of the gas
is the initial volume of the gas
is the number of moles
is the gas constant
is the initial temperature of the gas
By re-arranging this equation, we can find
:
2) Now the gas cools down to a temperature of
while the pressure is kept constant:
, so we can use again the ideal gas law to find the new volume of the gas
3) In a process at constant pressure, the work done by the gas is equal to the product between the pressure and the difference of volume:
by using the data we found at point 1) and 2), we find
where the negative sign means the work is done by the surrounding on the gas.
Answer:
<em>Vernal equinox, autumnal equinox, march equinox, September equinox, northward equinox and southward equinox </em><em>are the names for the equinoxes.
</em>
<u>Explanation:
</u>
There are different names which are named depending on the <em>month of the year when these equinox occurs and depends upon direction of motion of the sun</em>.<em> Equinox is a point where day time and night time have exactly equal length of time.</em>
Equinox occurs <em>twice</em> in a year and this occurs when <em>earth's equator passes through the sun</em>. We can say that equinox occurs when the sun’s center is directly above the equator.
Answer:
176.58Watts
Explanation:
Power= work done /time
Where mass(m)=60kg
Height (h) =3m
Time(s)=10s
Force of gravity = 9.81m/s^2
Power=mgh/t
Power= (60kg) * (9.81m/s^2) * (3m)/10s
Power= 176.58Watts
Answer:
when the ball is at its highest in the air.
Explanation:
I don't know for sure, but when the ball is in the air it has potential energy to fall(or something like that).
Answer:
Explanation:
Work is the product of force and distance, so the formula is:
The work is 6.00 Joules, but
- 1 Joule (J) is equal to 1 Newton meter (N*m).
- Therefore, the work of 6.00 J is equal to 6.00 N*m
The force is 2.50 Newtons.
The known values are:
Substitute the values into the formula.
We are solving for distance, so we must isolate the variable, d. It is being multiplied by 2.50 Newtons and the inverse of multiplication is division. Divide both sides by 2.50 N.
The units of Newtons cancel out.
The force was applied to the rock over a distance of <u>2.40 meters</u> and choice <u>C</u> is correct.