The elastic potential energy of a spring can be said to be the energy possessed by a spring due to a force that compresses or stretches the spring. This can also be said to be the work which is done by the applied force against the restoring force of the spring, which is stored as the elastic potential energy.
The elastic potential of a spring can be expressed as:
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The answer is C upwards at 20cm
As you said p=w/t.
but, w=f×s
=500×5=2500j
t=10s
p=w/t
=2500/10=250 watts
Answer with Explanation:
We are given that
Egood=12 V
Rbatt,good=0.02ohm
Edead=10.8 V
Rbatt,dead=0.3 ohm
We have to find the current through the batteries connected in series and parallel.
When batteries are connected in series
V=Egood+Edead=12+10.8=22.8 V
R=Rbatt,good+Rbatt,dead=0.02+0.3=0.32 ohm
Current,I=
Using the formula
When the batteries are connected in parallel
V=Egood-Edead=12-10.8=1.2 V
R=0.02+0.3=0.32 ohm
That was his student, Johannes Kepler.