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Nat2105 [25]
3 years ago
8

This year the boys’ basketball team won 4 times as many games as it lost. The team played a total of 40 games. How many games di

d the team win?
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

The team won 32 games.

Step-by-step explanation:

x = games won

y = games lost

z = total games = 40

x = 4y <em>Won 4 times as many games as it lost</em>

x + y = 40 <em>Games won + games lost = Total games played</em>

4y + y = 40 <em>Sub 4y in for x, as established previously</em>

5y = 40

y = 8

x = 4y

x = 4(8)

x = 32

The team won 32 games.

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Find the product of 52.6 x 9
marta [7]

Answer: 473.4

Step-by-step explanation: if you can't solve it, break the first number apart, multiply both numbers, then add them together. That way there not such big numbers :)

8 0
3 years ago
Hey if you could help me with this it'd mean a lot I can't figure it out
Blababa [14]

Answer:

L = 12  S = 5

Step-by-step explanation:

L+S=17

3L+2S=46

Multiply the first equation by -2

-2L -2S = -34

Then add it to the second equation

-2L -2S = -34

3L+2S=46

------------------

L = 12

Now we can find S

L+S = 17

12 + S = 17

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S = 17-12

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6 0
3 years ago
Bilal's favorite colors are red and green.
Arte-miy333 [17]

Answer:

P(A∪B) = 1/3

Step-by-step explanation:

Red  Garments = 1 red shirt + 1 red hat  + 1 red pairs of pants

Total Red Garments = 3

Green Garments =  1 green shirt + 1 green scarf + 1 green pairs of pants

Total Green Garments = 3

The total number of garments =  Total Red Garments + Total Green Garments:

3 + 3 = 6

Let A be the event that he selects a green garment

P(A) = Number of required outcomes/Total number of possible outcomes

P(A) =  3/6

Let B be the  event that he chooses a scarf

P(B) = 1/6

The objective here is to determine P(A or B) = P(A∪B)

Using the  probability set notation theory:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∩B) = Probability that a green pair of pant is chosen = P(A) - P(B)

= 3/6-1/6

= 2/6

P(A∪B) = 1/2 + 1/6 - 2/6

P(A∪B) = 2/6

P(A∪B) = 1/3

8 0
3 years ago
Read 2 more answers
The roots of $3x^2 - 4x + 15 = 0$ are the same as the roots of $x^2 + bx + c = 0,$ for some constants $b$ and $c.$ Find the orde
Akimi4 [234]

we are given

quadratic equation as

3x^2-4x+15=0

now, we can find b and c from

x^2+bx+c=0

we can see that coefficient of x^2 is 1

so, we will have to make coefficient x^2 as 1

so, we divide both sides by 3

3x^2-4x+15=0

\frac{3x^2-4x+15}{3}= \frac{0}{3}

\frac{3x^2}{3}-\frac{4x}{3}+\frac{15}{3}= \frac{0}{3}

now, we can simplify it

x^2-\frac{4}{3}x+5= 0

now, we can compare it with

x^2+bx+c=0

we get

b=-\frac{4}{3}

c=5

so, we get order pair as

(b,c)=(-\frac{4}{3} , 5)..............Answer

6 0
3 years ago
Read 2 more answers
Please help me fast and show all your work please thx ​
MrMuchimi
7x4x5= 140
Hope this helps!
7 0
3 years ago
Read 2 more answers
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