<u>Answer:</u>
The time taken for the ball to hit the floor as 1.02 seconds
<u>Explanation:</u>
As per the given question, the ball leaves at a speed from the table with an initial velocity of 10 m/s, we have the equation
where Vf represents the final velocity
Vi represents the initial velocity
a represents the acceleration and
t represents the time
after rearranging
= 1.022 seconds
If you know the real modulus of the cable (Y), the length, and the area (based on the radius), you can compute the spring constant, k = AE/L. Then, if you know the force used, you can compute the displacement, using F = kd, or d = F / k = FL/(AE). Our answer should work out to units of length. So,
d = 803 N * 9.06 m / [pi*(0.574 cm)^2 * 2.0 x 10^11 N/m^2]
d = 3.5 x 10^-8 Nm^3 / (cm^2 * N)
d = 3.5 x 10^-8 m^3 / cm^2 * (100 cm / 1 m)^2
d = 3.5 x 10^-4 m
Answer:
A
Explanation:
suddenly part of the force pulling to the left is gone.
and now the force pulling to the right is stronger.
so, the rope will move to the right. and that is also the direction of the net force.
Answer:
i think you would have to divide to 2 numbers to get the sum
Explanation:
By the Newtons Second Law:
F = ma
F = (47 kg)(15 m/s²)
<h2>F = 705 N</h2>
