Two point charges attract each other with an electric force of magnitude F. If the charge on one of the particles is reduced to
1 answer:
You might be interested in
Answer: The correct answer is option b.
Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.
The acceleration of the rocket is
To calculate the distance of rocket, we use third equation of motion, which is:
where, v = final velocity = 445m/s
u = initial velocity = 0m/s
a = acceleration =
s = distance = ? m
Putting values in above equation, we get:
Answer:x=79,202.77 ft
Explanation:
Given
plane is at a height of 32000 ft
angle of depression is
let x the distance between the point directly below the plane and airport be x
from diagram
x=79,202.77 ft
distance between plane and airport
h=85,422.94 ft
