1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liubo4ka [24]
3 years ago
14

If the change in velocity increases, what happens to the acceleration during the same time period?

Physics
2 answers:
Anna35 [415]3 years ago
7 0
The answer is the acceleration increases 
sineoko [7]3 years ago
4 0

Answer:

Explanation:

acceleration increases

You might be interested in
Charge is uniformly distributed around a ring of radius R and the resulting electric field magnitude E is measured along the rin
Arte-miy333 [17]

Answer:

x=\dfrac{r}{\sqrt2}

Explanation:

Given that

Radius =r

Electric filed =E

Q=Charge on the ring

The electric filed at distance x given as

E=K\dfrac{Q}{(r^2+x^2)^{3/2}}

For maximum condition

\dfrac{dE}{dx}=0

E=K{Q}{(r^2+x^2)^{-3/2}}

\dfrac{dE}{dx}=K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}

For maximum condition

\dfrac{dE}{dx}=0

K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}=0

r^2+x^2-3x^2=0

x=\dfrac{r}{\sqrt2}

At x=\dfrac{r}{\sqrt2} the electric field will be maximum.

3 0
3 years ago
ONLY TWO ANSWER CHOICES!!
Otrada [13]
A: Buoyant force is equal to the weight
3 0
3 years ago
A 1500kg car double its speed from 50km/h to 100km/h. By how many times does the kinetic energy from the car's forward motion in
Rashid [163]

Answer:

Explanation:

Inital KE = (1/2) m v^2 = (1/2) * 1500 * 50^2 = 1,875,000 J  

Final KE = (1/2) * 1500 * 100^2 = 7,500,000 J  

But  ,

4 * 1875000 = 7500000

so the KE has increased by 4 times.

8 0
3 years ago
Read 2 more answers
Two point charges each have a value of 3.0 c and are separated by a distance of 4.0 m. what is the electric field at a point mid
swat32
 <span>Place a test charge in the middle. It is 2cm away from each charge. 
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point. 
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out. 
THIS IS A TRICK QUESTION. 
THe electric field exactly midway between them = 0/Q = 0. 
But if the point moves even slightly you need the following formula 
F= (1/4Piε)(Q1Q2/D^2) 
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>
4 0
3 years ago
1. Explain who is doing more work and why: a bricklayer carrying bricks and placing them on the wallof a building being
Basile [38]
Both are doing because they have chorus
7 0
2 years ago
Other questions:
  • Ma puteti ajuta sa rezolv la fizica o problema ?
    15·1 answer
  • What is the formula for calculating the force and acceleration of an object?{physical science}:)
    8·1 answer
  • Explain why some objects fall faster than other objects,
    12·1 answer
  • The stair stepper is a novel exercise machine that attempts to reproduce the work done against gravity by walking up stairs. Wit
    7·1 answer
  • Which of the following has kinetic energy? (1 point)
    8·1 answer
  • Hi = L(1 – cos theta), theta = 40
    12·1 answer
  • Please help me on this!
    15·1 answer
  • What's a beam of light?<br>​
    8·1 answer
  • 9. Electron travelling though two horizontal plates
    9·1 answer
  • What cultular value does this melodic line portray?<br>a.jubilant<br>b.reserved<br>c.rich<br>d.poor​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!