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liubo4ka [24]
3 years ago
14

If the change in velocity increases, what happens to the acceleration during the same time period?

Physics
2 answers:
Anna35 [415]3 years ago
7 0
The answer is the acceleration increases 
sineoko [7]3 years ago
4 0

Answer:

Explanation:

acceleration increases

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Antireflection coatings can be used on the inner surfaces of eyeglasses to reduce the reflection of stray light into the eye, th
Basile [38]

Answer:

1.33

Explanation:

Using the formula for destructive interference since the two reflected ray light waves from eyeglass should be made to cancel each other ( destructive interference) and also refractive index of air less than the refractive index of the film and both are less than the refractive index of the glass meaning the both reflected rays from the air and film will experience a phase change

n film =  ( m + 0.5) ( λ / 2t)

since 2 t = ( m + 0.5) ( λ / n film)

where m is an integer, λ is wavelength, and t is thickness  and n film is the refractive index of film

for effectiveness m = 0

n film = ( 0.5) ( 480 ÷ (2 × 90 ) ) = 1.33

4 0
4 years ago
Physical science!!!!!!helpppp
ipn [44]

Answer:

Option B

10.36 m/s

Explanation:

Using the first given equation, then velocity=distance/time

Since distance is provided as 200 m and time, t is 19.3 seconds then substituting these figures yields

v=200/19.3=10.3626943

Rounding off to 2 decimal places, then

v=10.36 m/s

6 0
3 years ago
Simplified. The absorption spectra of ions have been used to identify the presence of the elements in the atmospheres of the sun
Nookie1986 [14]

Answer:

The answer is "3.83 \times 10^9 \ m"

Explanation:

Z=2, so the equation is E= \frac{-4B}{n^2}

Calculate the value for E when:  

n=2 and n=9

The energy is the difference in transformation, name the energy delta E Deduct these two energies  

In this transition, the wavelength of the photon emitted is:

\Delta E=2.18 \times  10^{-18} ( \frac{1}{4}- \frac{1}{81})

\lambda = \frac{h c}{\Delta E}

h ( Planck's\  constant) = 6.62 \times  10^{(-34)} \ Js \\\\ speed \ of \ light = 3 \times 10^{8} \ \frac{m}{s}\\\\= \frac{6.62 \times 10^{(-34)} \times 3 \times 10^ {8}}{2.18 \times  10^{-18}} (\frac{1}{4}- \frac{1}{81}) \\\\=3.83 \times 10^9 \ m\\\\

6 0
3 years ago
What causes air to move or circulate from one place to another?
MAXImum [283]

Answer:

c

Explanation:

simple

3 0
3 years ago
Read 2 more answers
1. A car accelerates uniformly from 12 m/s to 39 m/s in 12 seconds. What is the car's average acceleration
Alinara [238K]

Answer:

(1) 2.25m/s^2

(2) 45.6m

Explanation:

(1) A car accelerates uniformly from 12m/s to 39m/s in 12 seconds

Therefore the average acceleration can be calculated as follows

a = 39-12/12

a = 27/12

a= 2.25m/s^2

(2) A butterfly is flying at 4m/s , it accelerates uniformly at 1.2 m/s for 6 seconds

u= 4

a= 1.2

t= 6

Therefore the distance can be calculated as follows

S= ut + 1/2at^2

= 4×6 + 1/2 × 1.2 × 6^2

= 24 + 1/2 × 1.2 × 36

= 24 + 1/2 × 43.2

= 24 + 21.6

S = 45.6m

Hence the butterfly travels at 45.6m

5 0
3 years ago
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