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4 years ago

Simplify 2/3 (12 – 21c) Enter your answer in the

Mathematics

2 answers:

Snowcat [4.5K]4 years ago

8 0

Answer:

8-14c

Step-by-step explanation:

2/3 (12 – 21c)

2/3(12)-2/3(21c) [distribute property]

8-14c

mixas84 [53]4 years ago

8 0

Step-by-step explanation:

2/3(12-21c)=2(4-7c)=8-14c

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Four batsmen on a cricket team had a mean of 42.5 runs the other 7 batsmen had a mea of 18 what was the mean number of scored by

Ira Lisetskai [31]

Answer:

The mean score of the entire team is 26.909.

Step-by-step explanation:

Given that four batsmen had a mean of 42.5.

Let $\textbf{B}_{\textbf{i}$ , where $i = 1, 2, 3, \hdots, 11$ denote the batsmen.

From the first statement, we have:

$\frac{B_1 + B_2 + B_3 + B_4}{4} = 42.5$

$\implies B_1 + B_2 + B_3 + B_4 = 42.5 \times 4 = \textbf{170}$

Therefore, the sum of the scores of the first four batsmen is 170.

Now, from the second statement we have:

$\frac{B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{7} = 18$

$\implies B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11} = 18 \times 7 = \textbf{126}$

That is, the sum of the scores of the remaining 7 batsmen is 126.

Now, to calculate the average(mean) of the entire team, we add the individual scores and divide it by 11.

$\implies \frac{B_1 + B_2 + B_3 + B_4 + B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{11} = \frac{170 + 126}{11}$

$= \frac{296}{11}$

$= \textbf{26.90}$ which is the required answer.

8 0

3 years ago

Data from the U.S. Department of Education indicates that 46% of business graduate students from private universities had studen

hoa [83]

Answer:

For this case the mean is given by:

$\mu = p =0.46$

And the standard deviation would be:

$\sigma = \sqrt{\frac{0.46*(1-0.46)}{215}}= 0.0340$

Step-by-step explanation:

For this case we have the following info given :

$n = 215$ represent the sample size

$p = 0.46$ represent the proportion of business graduate students from private universities had student loans

For this case we want to find the distribution for the sample proportion and we know that this distribution is given by:

$\hat p \sim N (p , \sqrt{\frac{p(1-p)}{n}})$

And for this case the mean is given by:

$\mu = p =0.46$

And the standard deviation would be:

$\sigma = \sqrt{\frac{0.46*(1-0.46)}{215}}= 0.0340$

7 0

4 years ago

Read 2 more answers

What is the value of the expression r +1988 if r =2976

OlgaM077 [116]

I think 4,967

Substitue r with 2976-

r +1988 to 2976 +1988

/-

8 0

4 years ago

Rewrite the following polynomial in standard form 5x-4-3x²+2x²

Lunna [17]

The standard form of the polynomial is expressed as $P(x)=-x^2+5x - 4$

<h3 /><h3>The standard form of a polynomial</h3>

The standard form of a polynomial is degree 3 is expressed as:

$P(x) = ax^3+bx^2+cx+d$

Given the expression 5x-4-3x²+2x², we are to write it in standard form. The standard form is expressed as shown:

Collect the like terms;

$5x-4-3x^2+2x^2$

$-3x^2+2x^2+5x-4|\\$

Group the terms:

$P(x) = (-3x^2+2x^2+5x-4)\\P(x)=-x^2+5x - 4$

Hence the standard form of the polynomial is expressed as $P(x)=-x^2+5x - 4$

Learn more on polynomial here: brainly.com/question/4142886

5 0

2 years ago

Read 2 more answers

76.<br>175/50<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B175%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B50%7D%20%

kramer

Answer:

Step-by-step explanation:

Factorize 175 and 50

175 = 5 * 5 * 7

50 = 5 * 5 * 2

$\frac{\sqrt[3]{175}}{\sqrt[3]{}50}=\sqrt[3]{\frac{175}{50}}\\\\\\ =\sqrt[3]{\frac{5*5*7}{5*5*2}}\\\\\\=\sqrt[3]{\frac{7}{2}}$

7 0

3 years ago