To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
Answer:
And replacing we got:

Step-by-step explanation:
Let X the random variable of interest "number of craked eggs", on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
And we want to find this probability:
And we can find the probability:
And replacing we got:

Answer:
$693
Step-by-step explanation:
Catherine invested a principal of $1,650 in her bank account with;
interest rate of 3.1%
How much interest did she earn in 14 years?
To find the amount accumulated in the 14 years, we use the formula:
A = P(1 + rt)
Where A is the amount accumulated, P is the principal, r is the interest rate and t is the time.
A = $1650(1 +
(14))
A = $1650 + $693 = $2343
Interest = Amount (A) - Principal (P) = $2343 - $1650 = $693
Answer:
d for the first and c for the second
Step-by-step explanation:
1. both are solid lines so it is or equal to something. the first line is going down by -3 and crosses the y axis at -3 so it is _>_ - 3x-3
the second line is going down at -1/2 and crosses the y axis at 2 so it is _<_ -1/2x+2
2. The point where the two lines cross is at (2.5, -6.5)
Answer:
25
Step-by-step explanation:
90 - 65 = 25
Therefore, x is 25
Thenks and mark me brainliest :))