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Dmitrij [34]
3 years ago
15

How reactive is an atom of Sodium (na) and why?

Chemistry
1 answer:
Dmitrij [34]3 years ago
3 0
The water and sodium first combine, the sodium releases electrons — negatively charged particles — leaving the element in a positively charged state All those positive charges repel each other, tearing the sodium apart and creating more surface area for an even bigger reaction: ka-boom. 
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A hydrogen ion, H+, is the same as a.... <br> PLEASEEE
sdas [7]

It is the same as a proton. That is why, if hydrogen was a molecule not an ion, one electron is needed to 'cancel' out the proton.

5 0
3 years ago
Un tecnico di laboratorio deve preparare una soluzione di carbonato di sodio decaidrato, Na2CO3⋅ 10 H2O per eseguire alcune anal
fiasKO [112]

Answer:

1.  3.70 g Na₂CO₃·10H₂O

2. 50.0 mL of the first solution

Explanation:

1. Prepare the solution

(a) Calculate the molar mass of Na₂CO₃·10H₂O

\begin{array}{rrr}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 2\times22.99 & 45.98\\\text{1C} & 1\times 12.01 & 12.01\\\text{13O}&13 \times16.00 & 208.00\\\text{20H}&20 \times 1.008 & 20.16\\&\text{TOTAL =} & \mathbf{286.15}\\\end{array}

The molar mass of Na₂CO₃·10H₂O is 286.15 g/mol.

(b) Calculate the moles of Na₂CO₃·10H₂O

\text{Moles of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}\\= \text{0.250 L solution} \times \dfrac{\text{0.0500 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}{\text{1 L solution}}\\\\= \text{0.0125 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}

(c) Calculate the mass of Na₂CO₃·10H₂O

\text{Mass of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O }\\= \text{0.012 50 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O } \times \dfrac{\text{296.15 g Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}{\text{1 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}\\\\= \text{3.70 g Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}\\\text{You need $\large \boxed{\textbf{3.70 g}}$ of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}

2. Dilute the solution

We can use the dilution formula to calculate the volume needed.

V₁c₁ = V₂c₂

Data:

V₁ = ?;            c₁ = 0.0500 mol·L⁻¹

V₂ = 100 mL; c₂ = 0.0250 mol·L⁻¹

Calculation:

\begin{array}{rcl}V_{1}c_{1} & = & V_{2}c_{2}\\V_{1}\times \text{0.0500 mol/L} & = & \text{100 mL} \times\text{0.0250 mol/L}\\0.0500V_{1}& = & \text{2.500 mL}\\V_{1}&=& \dfrac{\text{2.500 mL}}{0.0500}\\\\& = &  \text{50.0 mL}\\\end{array}\\\text{You need $\large \boxed{\textbf{50.0 mL}}$ of the concentrated solution.}

7 0
3 years ago
6.00g of gold was heated from 20.0c to 22.0c. How much heat was applied to the gold
Alinara [238K]
6 x .129 x 2= 1.55J
q = mass x specific heat x delta T.
5 0
2 years ago
Which of the following is chemically inert ( unreactive)?
IrinaK [193]

(C) neon (atomic number 10)

Explanation:

The atom that is chemically inert is Neon with an atomic number of 10.

An atom is chemically inert if it does not willingly take part in chemical reaction.

Atoms takes part in chemical reactions in order to attain a stable configuration as seen in the noble gases.

In the noble gases every enable level is completely filled with the appropriate number of electrons.

  • The noble gases are He, Ne, Ar, Kr, Xe
  • These elements do not react with others.
  • From the given option, Neon is a noble gas and therefore inert.

learn more:

Noble gas brainly.com/question/1781595

#learnwithBrainly

4 0
4 years ago
Predict the shape of the molecule.
GuDViN [60]

Number of electron pairs = \frac{1}{2}[V+N-C+A]

2

1

[V+N−C+A]

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

SbCl_5SbCl

5

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In the given molecule, antimony is the central atom and there are five chlorine as monovalent atoms.

The number of electron pairs are 5 that means the hybridization will be sp^3dsp

3

B and geometry of the molecule will be trigonal bipyramidal.

6 0
2 years ago
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