<span>n = PV / RT = 733 torr *0.961 L / 62.363 L torr K^-1 mol^-1 * 294 K = 0.038419617 mol </span>
Answer:
A. How the concentration of the reactants affects the rate of a reaction
Explanation:
Let's consider a generic reaction.
A + B ⇒ Products
The generic rate law is:
rate = k × [A]ᵃ × [B]ᵇ
where,
- rate: rate of the reaction
- [A] and [B]: molar concentrations of the reactants
As we can see, the rate law shows how the concentration of the reactants affects the rate of a reaction.
The balanced chemical reaction is:
<span>Ca + Cl2 = CaCl2
</span>
We are given the amount of calcium metal to be used for this reaction. This will be the starting point for the calculations.
56 g Ca ( 1 mol Ca / 40.08 g Ca) (1 mol Cl2 / 1 mol Ca) ( 22.414 L Cl2 / 1 mol Cl2 ) = 31.32 L Cl2 gas produced from the reaction
Answer:
857.2947
Explanation:
You start with what you’re given 82g of H20 and multiply by 1 mole and the actual grams of h20 which is 18.0 then you do the mole. 1 mol of O2 and 2 mol of H2O times 6.02 x 10^23
The empirical formula of this compound is equal to
.
<h3>
Empirical formula</h3>
To calculate the empirical formula of a compound, it is necessary to know the number of moles present.
Therefore, we will use the molar mass of iron and oxygen to find the amount of moles, so that:






Finally, as the empirical formula is composed of integers numbers of moles, just multiply the values by the smallest common factor to transform into an integer, so that:
O => 
Fe => 
So, the empirical formula of this compound is equal to 
Learn more about empirical formula in: brainly.com/question/1363167