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vagabundo [1.1K]
3 years ago
15

What role does the mantle play in the rock cycle?

Chemistry
2 answers:
solniwko [45]3 years ago
7 0
Glaciers are an important part of the rock life cycle. The part they play is to break huge rock faces into smaller pieces, as well as to move rocks from one place to another, while grinding them into pebbles and sand.
UkoKoshka [18]3 years ago
3 0
Weathering and Erosion. They are part of the process.
@Google.
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A mixture of oxygen hydrogen and nitrogen gas is exerts a total pressure of 282K PA if the partial pressures of oxygen and hydro
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Read 2 more answers
Astroturf is a durable artificial surface used to cover athletic fields. A soccer field 0.06214- mile-long by 253 ft wide is cov
love history [14]

Answer:

The weight of the Astroturf is 179,684.31 Newtons.

Explanation:

Length of a soccer field = 0.06214 mile = 328.0992 feet

(1 mile = 5280 feet)

Breadth of a soccer field  = 253 feet

Length of a Astroturf which soccer field is to be covered, l = 328.0992 feet

Breadth of a Astroturf which soccer field is to be covered ,b = 253 feet

Thickness of a Astroturf with which soccer field is to be covered = h

h = ½ inch = 0.5 inch = 0.041665 feet

(1 inches = 0.08333 feet)

Volume of the Astroturf ,V= l × b × h

V=328.0992 ft\times 253 ft\times 0.041665 ft=3,458.574 ft^3

Mass of the Astroturf = m

Density of the Astroturf = d = 187 oz/ft^3

d=\frac{m}{V}

m=d\times V= 187 oz/ft^3\times 3,458.574 ft^3=646,753.35 oz

1 oz = 0.0283495 kg

m=646,743.35 oz=646,743.35\times 0.0283495 kg=18,335.13 kg

Weight of the Astroturf = W

W = mg

=W=18,335.13 kg\times 9.8 m/s^2=179,684.31 N

The weight of the Astroturf is 179,684.31 Newtons.

8 0
3 years ago
This is not a homework question
Dovator [93]
What state you live in? because I know someone who does it for free
8 0
3 years ago
How many moles of h2 can be formed if a 3.25g sample of Mg reacts with excess HCl
kogti [31]

Answer:

0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl

Explanation:

The balanced reaction is:

Mg + 2 HCl → MgCl₂ + H₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles react:

  • Mg: 1 mole
  • HCl: 2 moles
  • MgCl₂: 1 mole
  • H₂: 1 mole

Being:

  • Mg: 24. 31 g/mole
  • H: 1 g/mole
  • Cl: 35.45 g/mole

the molar mass of the compounds participating in the reaction is:

  • Mg: 24.31 g/mole
  • HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
  • MgCl₂: 24.31 g/mole + 2*35.45 g/mole= 95.21 g/mole
  • H₂: 2*1 g/mole= 2 g/mole

Then, by stoichiometry of the reaction, the following quantities of mass participate in the reaction:

  • Mg: 1 mole* 24.31 g/mole= 24.31 g
  • HCl: 2 moles* 36.45 g/mole= 72.9 g
  • MgCl₂: 1 mole* 95.21 g/mole= 95.21 g
  • H₂: 1 mole* 2 g/mole= 2 g

Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg form 1 mole of H₂, 3.25 grams of Mg how many moles of H₂ will they form?

moles of H_{2} =\frac{3.25 grams of Mg*1 mole of H_{2} }{24.31 grams of Mg}

moles of H₂= 0.134

<u><em>0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl</em></u>

7 0
3 years ago
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