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UNO [17]
2 years ago
7

PLEASE HELP ME WITH THIS QUESTION THIS FREAKING SUCKS

Chemistry
1 answer:
tigry1 [53]2 years ago
8 0

Answer:

m = 0.122 m

Explanation:

Molality(m): A measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent.

\mathrm{Molality\:Formula}:\quad \mathrm m =  \dfrac{ mole\:of\:solute  }{ mass\:of\:solvent\:in\:kg  }

\mathrm m =  \dfrac{ mole}{ kg  }

\mathrm{Substitute\:the\:numbers\:into\:the\:"Molality\:Formula"}

\mathrm m =   \dfrac{ 0.250  }{ 2.05  }

\mathrm{Divide\:0.250\:by\:2.05\:and\:get\:0.12195122}

\mathrm m =   {0.12195122}

\mathrm{Round\:to\:the\:nearest\:thousandths\:place}

\mathrm m =   0.122

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Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta
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Answer:

147.2g

Explanation:

The full solution can be found in the image attached. Graham's law was applied to the problem. The rate of diffusion of a gas is inversely proportional to its molar mass or vapour density. Molar mass= 2vapour density

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For each of the following sublevels, give the n and l values and the number of orbitals: (a) 5s; (b) 3p; (c) 4f
OverLord2011 [107]

Answer:

(a) 5s. n = 5. Sublevel s, l = 0. Number of orbitals = 1

(b) 3p. n = 3. Sublevel p, l = 1. Number of orbitals = 3

(c) 4f. n =4. Sublevel f, l = 3. Number of orbitals = 7

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Sublevel number, 0 ≤ l ≤ n − 1

So,

(a) 5s. n = 5, shell number 5. Sublevel s, l = 0. Number of orbitals = 2l +1 = 1

(b) 3p. n = 3, shell number 3. Sublevel p, l = 1. Number of orbitals = 2l +1 = 3

(c) 4f. n =4, shell number 4. Sublevel f, l = 3. Number of orbitals =  2l +1 = 7

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Which of the following do water, rust, and salt have in common?
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A sample of gas has a volume of 20.0 mL at STP. What will the volume be if the temperature is changed to 546 K and the pressure
Ostrovityanka [42]

The volume did not change, it remained at 20 ml

<h3>Further explanation</h3>

Given

20 ml a sample gas at STP(273 K, 1 atm)

T₂=546 K

P₂=2 atm

Required

The volume

Solution

Combined gas Law :

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

Input the value :

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The volume does not change because the pressure and temperature are increased by the same ratio as the initial conditions (to 2x)

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2 years ago
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