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vichka [17]
3 years ago
8

Predict the reaction HCIO4+ KOH=

Chemistry
2 answers:
Hatshy [7]3 years ago
7 0

Answer:

HCIO4 + KOH → KCIO4 + H2O

Explanation:

nailed it

Helga [31]3 years ago
6 0

Answer:

HClO4 + KOH → KClO4 + H2O

Explanation:

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d cell membrane:)

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3. Oblicz stężenie procentowe 423 g roztworu zawierającego 17 g rozpuszczonego siarczanu (VI) miedzi (II). Zapisz obliczenia i o
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17 / 423 = 0.04018912529

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You will analyze four substances in this lab. Based on their chemical formulas and what you already know about covalent and ioni
Phoenix [80]

Answer: Oil: covalent

Cornstarch: Covalent

Sodium chloride: Ionic

Sodium bicarbonate: Ionic

Explanation: Covalent compounds are formed by sharing of electrons between non metals whereas ionic compounds are formed by transfer of electrons from metals to non metals.

1. Oil, which is built from the nonmetals hydrogen, carbon, and oxygen: forms a covalent compound by sharing of electrons between non metals hydrogen, carbon, and oxygen. Covalent compounds are insoluble in water.

2. Cornstarch, a carbohydrate consisting of hydrogen, carbon, and oxygen: forms a covalent compound by sharing of electrons between non metals hydrogen, carbon, and oxygen. Covalent compounds are insoluble in water.

3. Sodium chloride (table salt), whose formula is NaCl is formed by transfer of electrons from sodium to chlorine.Ionic compounds are soluble in water.

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7 0
3 years ago
Read 2 more answers
Nitric oxide reacts with chlorine gas according to the reaction: 2 NO( g) + Cl2( g) ∆ 2 NOCl( g) Kp = 0.27 at 700 K A reaction m
11Alexandr11 [23.1K]

Answer:  The initial partial pressures of NO and Cl_2 is 139.4 torr.

Explanation:

The equilibrium reaction is

                           2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

initially conc.         p            p                  0

At eqm.                p-2x        p-x               2x

Given: p_{NOCl}= 2x= 115torr

x=57.5 torr

The expression for equilibrium constant is :

K_p=\frac{p_{NOCl}^2}{p_{NO}^2\times p_{Cl_2}}

p_{NOCl} = 2x =115 torr

p_{NO} = (p-2x) = p-115 torr

p_{Cl_2} = (p-x)= p-57.5 torr

Now put all the given values in this expression, we get

0.27=\frac{(115)^2}{(p-115)^2\times (p-57.5)}

p=139.4torr

Therefore, the initial partial pressures of NO and Cl_2 is 139.4 torr.

8 0
3 years ago
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