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KengaRu [80]
3 years ago
9

After a party the host pours the remnants of several bottles of wine into a jug. He then inserts a cork with a 2.15-cm diameter

into the jug, placing it in direct contact with the wine. He is amazed when he pounds the cork into place that the bottom of the jug, with a 12-cm diameter, breaks away. show answer No Attempt Find the force that the liquid exerts on the bottom of the bottle when the host is pounding the cork with a 125-N force. Ignore the force caused by the weight of the wine.
Physics
1 answer:
pychu [463]3 years ago
5 0

Answer:

3893.99675 N

Explanation:

F_1  = 125 N

A_1 = \pi 1.075^2

A_2 = \pi 6^2

From Pascal's law

\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow F_2=\dfrac{F_1\times A_2}{A_1}\\\Rightarrow F_2=\dfrac{125\times 6^2}{1.075^2}\\\Rightarrow F_2=3893.99675\ N

The force that the liquid exerts on the bottom of the bottle is 3893.99675 N

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