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3 years ago

What structure holds donor sperm in earthworms

Physics

1 answer:

lidiya [134]3 years ago

4 0

Answer:

Explanation: As the earthworm passes through the slime tube, the tube will pass over the female pore picking up eggs. The tube will continue to move down the earthworm and pass over the male pore called the spermatheca which has the stored sperm called the spermatozoa.

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What does that mean?

Veseljchak [2.6K]

Answer:

acceleration

acceleration is the rate at which velocity change

i think

8 0

3 years ago

Read 2 more answers

A cube with sides of area 22 cm2 contains a 21.2 nanoCoulomb charge. Find the flux of the electric field through the surface of

VladimirAG [237]

Answer:

Explanation:

According to Gausses theorem, electric flux coming out of charge on all sides q is equal to

q / ε₀

q is charge , ε₀ is permittivity of air whose value is given by

8.85 x 10⁻¹²; q = 21.2 x 10⁻⁹ C

Putting the values we get

FLUX = $\frac{21.2\times10^{-9}}{8.85\times10^{-12}}$

2.4 x 10³ Nm²/C

3 0

3 years ago

PLS HELP I HAVE EXAM ILL GIVE U BRAINLIST

stiv31 [10]

Explanation:

False

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3 years ago

Which of the following most logically completes the argument below?

kolezko [41]

Answer:

(E) a greatly increased number of small particles in Earth’s orbit would result in a blanket of reflections that would make certain valuable telescope observations impossible

Explanation:

The trade is one strong reflection for many weak reflections (and more dangerous near-Earth space travel).

None of the answer choices except the last one has anything to do with the effect of exploding a satellite. When you are arguing that exploding a satellite is ill conceived, you need to address specifically the effects of exploding the satellite.

6 0

3 years ago

If an object is projected upward from ground level with an initial velocity of 144144 ft per sec, then its height in feet after

Liula [17]

Answer:

4.5 s, 324 ft

Explanation:

The object is projected upward with an initial velocity of

$v_0 = 144 ft/s$

The equation that describes its height at time t is

$s(t) = -16t^2 + 144 t$ (1)

where t, the time, is measured in seconds.

In order to find the time it takes for the object to reach the maximum height, we must find an expression for its velocity at time t, which can be found by calculating the derivative of the position, s(t):

$v(t) = s'(t) = -32t +144$ (2)

At the maximum heigth, the vertical velocity is zero:

v(t) = 0

Substituting into the equation above, we find the corresponding time at which the object reaches the maximum height:

$0=-32t+144\\t=\frac{144}{32}=4.5 s$

And by substituting this value into eq.(1), we also find the maximum height:

$s(t) = -16(4.5)^2+144(4.5)=324 ft$

3 0

3 years ago