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Andre45 [30]
3 years ago
14

If the wind or current is pushing your boat away from the dock as you prepare to dock, which line should you secure first?

Physics
2 answers:
sveta [45]3 years ago
5 0

The line that ought to be verified first in pushing the vessel

away from the dock in readiness to dock is the bow line. At the point when the bow line is  

Further explanation:

verified, it is ideal to switch it and go to the dock, this will draw in the  

line to fix such that will enable it to swing back in the dock.

Docking With Wind or Current from dock

Approach the dock gradually at a sharp edge (around 40 degrees).  

Utilize turn around to stop when near the dock. Secure the bow line.  

Put the pontoon in forward apparatus quickly, and gradually turn the guiding wheel hard away from the dock—this will swing in the stern. Secure the stern line.

Plane:

A point exists in zero measurements. A line exists in one measurement, and we indicate a line with two. A plane exists in two measurements. We determine a plane with three. Any two of the focuses determine a linea.

Thank you so much Hope will understand how this process will happen.

Answer Details:

Subject: Physics  

Level: High School

Key Words:

Further explanation:

Docking With Wind or Current From the Dock:

Plane:

For further Evaluation

brainly.com/question/1156977

brainly.com/question/10494507

Sphinxa [80]3 years ago
4 0

The line that should be secured first in pushing the boat away from the dock in preparation to dock is the bow line. When the bow line is secured, it is best to reverse it and turn to the dock, this will engage the line to tighten in a way that will help it swing back in the dock.

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Answer:

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Explanation:

The frequency of sound determines the sound. If the frequency is lower the pitch will be lower. If the frequency is higher the pitch will be higher. This is affected by the motion of the sound source because when a sound source is moving faster the frequency will become higher.

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A dog and a cat sit on a merry-go-round. The dog sits 0.3 m from the center. The cat sits 1.5 m from the center. The whole merry
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The motion map shows an object’s position and velocity at given times. A long black arrow right labeled x. Above that are 5 gree
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The map be changed <u>by adding vectors that are all the same length and placing them above the current top row of vectors</u>

<h3>Further explanation</h3>

A motion map represents the position, velocity, or acceleration of an object at various time readings

a small point or dot describes the position of the object. the object's velocity / acceleration is represented by an arrow / vector.

In this motion map, The arrows (vectors) are all the same length (same speed) and point in the same direction (direction to the right) for t = 0 (origin) to t = 4s

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The initial velocity of the bird before the gust of wind

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D. the amount of chemical energy equals the amount of heat and light energy.

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3 years ago
Unpolarized light with an intensity of 655 W / m2 is incident on a polarizer with an unknown axis. The light then passes through
Norma-Jean [14]

Answer:

1.\theta=29.84^{0}

2.\theta=60.15^{0}

Explanation:

Polarizes axis can create two possible angles with the vertical.

first we have to find the intensity of  first polarizer

which is given as

I=\frac{I_{0} }{2}

I= \frac{655\frac{W}{M^{2} } }{2}

I=327.5\frac{W}{m^{2} }

For a smaller angle for the first polarizer:

According to Malus Law

I_{2} =I_{1} Cos^{2}(90^{0} - \theta)

I_{2} =I_{1} sin^{2}\theta

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taking square root on both sides

\sqrt{\frac{163}{327.5} } = sin\theta

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\theta=29.84^{0}

For a larger angle for the first polarizer:

According to Malus Law

I_{2} =I_{1} cos^{2}\theta

\frac{I_{2} }{I_{1} }=Cos^{2}\theta

taking square root on both sides

\sqrt{\frac{163}{327.5} } = cos\theta

\theta=Cos^{-1}(0.4977)

\theta=60.15^{0}

7 0
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