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3 years ago

Millions of children are treated each year for sports-related injuries.

Physics

2 answers:

miv72 [106K]3 years ago

6 0

Answer:

True

Explanation:

As per a survey conducted in the United States, it has been highlighted that among 30 million children participating in any sports, there are 3.5 million children who face injuries. It is because of these injuries that the children have to take some leave or absence from the sports. Also, the statistics discloses the fact that among all the injuries faced by the humans, one third of them are related to the childhood sports activities. Sprains and strains are among the most common of the injuries.

s2008m [1.1K]3 years ago

5 0

Answer:

true

Explanation:

edge

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Answer:

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Explanation:

The peak wavelength of the spectral distribution can be found by using Wien's displacement law:

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3 years ago

A ray of light contains two colors: red with wavelength of 660 nm and blue with wavelength 470 nm. The ray passes through two na

densk [106]

Answer:

The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.

Explanation:

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$y'=\dfrac{470\times10^{-9}\times5.0}{0.30\times10^{-3}}$

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4 years ago

Explain the following statement: A concentrated acid is not necessarily a strong acid.

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3 years ago

Read 2 more answers

The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt

lesantik [10]

Answer:

(a) $\triangle l=5 mm$

(b) 0.033

Explanation:

(a)

Force F=mg where m is mass and g is acceleration due to gravity whose value is taken as $9.81 m/s^{2}$

However, for this case, the maximum force is 8 times the weight of runner hence F=8mg

Assume Young's modulus for tendon is $0.15*10^{10} N/m^{2}$

Young's modulus is given by

$E=\frac {Fl}{A\triangle l}$ and $\triangle l=\frac {Fl}{EA}$ and substituting F with 8mg we obtain $\triangle l=\frac {8mgl}{EA}$

Where E is young's modulus, l is stretched length and \triangle l is change in length

Substituting m as 70 kg, g as $9.81 m/s^{2}$ , l as 15cm=0.15 m, E as $0.15*10^{10} N/m^{2}$ and A as $110 m^{2}=0.000110 m^{2}$

$\triangle l=\frac {8*70 Kg*9.81 m/s^{2}*0.15m}{0.15*10^{10} N/m^{2} *0.00011 m^{2}}=0.004994182 m$

$\triangle l=5 mm$

(b)

Strain, $\epsilon=\frac {\triangle l}{l}$ and the fraction of tendon’s length is the ratio of change in length to the stretched length

The fraction of tendon, f is given by

$f=\frac {\triangle l}{l}$ . Substituting $\triangle l$ with 0.005m and l with 0.15m we obtain

$\epsilon=f=\frac {0.005}{0.15}=\frac {1}{30}=0.033$

Therefore, fraction of the tendon’s length is 0.033

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