Answer:
If the final question is; at what velocity will the first block start to move outward in m/s?

Explanation:
The motion have the velocity that will make the block move using:




μ
Resolving:





There's a short handy formula for that.
If the object is just dropped and not tossed, and it's not affected by air resistance on the way down, then the distance it falls in T seconds is
D = (1/2) (gravity) (T²)
For this problem . . .
176.4 m = (1/2) (9.8 m/s²) (T²)
Divide each side by (4.9 m/s²) :
T² = (176.4 m) / (4.9 m/s²)
T² = (36 s²)
Take the square root of each side:
<em>T = 6 seconds</em>
Answer:
2500m
Explanation:
given,
initial velocity(u) = 5m/s
final velocity (v) = 0 m/s ( as he/she stopped riding after 1000 secs)
time = 1000 secs
distance(s)=?
now,
s=( u+v ) ×t /2
=(5+0)×1000/2
=2500 m
hence, he /she travels 2500m far
Boyle’s law is P1V1 = P2V2. This shows that pressure and volume have an inverse relationship, so increase in pressure causes a decrease in volume. B is your answer