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Iteru [2.4K]
3 years ago
6

At what temperature do the fahrenheit and celsius scales give the same reading?

Physics
1 answer:
anygoal [31]3 years ago
7 0
At -40.

-40 gives the same reading for Fahrenheit and Celsius scale.
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The work of energy theorem states that an increase in net work results in what?
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It results change only in it's kinetic energy, it's KE will increase in accord with the work-energy theorem 
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Which statement represents a difference between horizontal and vertical relationships?
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D.) Vertical relationships involve unequal status, while horizontal relationships represent equal status.
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Which of the following is likely to contribute to geological events that take place on Earth?
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Crust sitting on top of Milton rock of the mantle
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Read 2 more answers
Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. Part A If the surfac
alukav5142 [94]

Answer:

5308.34 N/C

Explanation:

Given:

Surface density of each plate (σ) = 47.0 nC/m² = 47\times 10^{-9}\ C/m^2

Separation between the plates (d) = 2.20 cm

We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:

E=\dfrac{\sigma}{2\epsilon_0}

Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,

E_{between}=E+E=2E=\frac{2\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}

Now, plug in  47\times 10^{-9}\ C/m^2 for 'σ' and 8.85\times 10^{-12}\ F/m for \epsilon_0 and solve for the electric field. This gives,

E_{between}=\frac{47\times 10^{-9}\ C/m^2}{8.854\times 10^{-12}\ F/m}\\\\E_{between}= 5308.34\ N/C

Therefore, the electric field between the plates has a magnitude of 5308.34 N/C

5 0
3 years ago
3. Sailors use a capstan (shown below) to raise and lower the anchor. It takes two sailors located 1 meter from the center to tu
mr_godi [17]

Answer:

B. 2 meters.

Explanation:

To rotate the capstan a certain amount of torque is required, and if each sailor applies a force F at a distance D from the center, then for two sailors the total torque will be

\tau = 2FD\\;

therefore,  for one sailor to apply the same torque it must be that the torque \tau_2 he applies must be equal to the torque that the two sailors applied:

FD_2 =2FD

which gives

D_2 = 2D.

and since D = 1\:meter,

\boxed{D_2 = 2\: meters}

which is choice B.

4 0
3 years ago
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