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3 years ago

What is kelvin?(scientifically plz)

Physics

1 answer:

IgorC [24]3 years ago

4 0

Answer:

The kelvin is the base unit of temperature in the International System of Units, It is named after the Belfast-born, Glasgow University engineer and physicist William Thomson.There are 100 degrees between the temperate at which water freezes at (273.16 K) and boils (373.16 K). Each unit on this scale, called a Kelvin rather than a degree, is equal to a degree on the Celsius scale. For this reason, just the K, not the degree symbol, is used when reporting temperatures in Kelvin.

Explanation:

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The person has an upward acceleration of 0.70 m/s^2 and is lifted from rest through a distance of 13 m. A rescue helicopter lift

Alex

Answer:

840 N

10920 J

- 10192 J

4.3 m/s

Explanation:

T = tension force in the cable in upward direction = ?

a = acceleration of the person in upward direction = 0.70 m/s²

m = mass of the person being lifted = 80 kg

Force equation for the motion of person in upward direction is given as

T - mg = ma

T = m (g + a)

T = (80) (9.8 + 0.70)

T = 840 N

d = distance traveled in upward direction = 13 m

$W_{t}$ = Work done by tension force

Work done by tension force is given as

$W_{t}$ = T d

$W_{t}$ = (840) (13)

$W_{t}$ = 10920 J

d = distance traveled in upward direction = 13 m

$W_{g}$ = Work done by person's weight

Work done by person's weight is given as

$W_{g}$ = - mg d

$W_{g}$ = - (80 x 9.8) (13)

$W_{g}$ = - 10192 J

$F_{net}$ = Net force on the person = ma = 80 x 0.70 = 56 N

v₀ = initial speed of the person = 0 m/s

v = final speed

Using work-energy theorem

$F_{net}$ d = (0.5) m (v² - v₀²)

(56) (13) = (0.5) (80) (v² - 0²)

v = 4.3 m/s

6 0

3 years ago

a ball is thrown straight up with an initial speed 40m/s.a) how high does it go? b) what will be its velocity be in 7 secs?c) ho

Vinil7 [7]

By how much would its speed reading increase with each second of fall? ... Ex 3.24 For a freely falling object dropped from rest, what is its acceleration at the end of the 5th second ... Pb 3.3 A ball is thrown straight up with an initial speed of 30 m/s. How high does it go, and how long is it in the air (neglecting air resistance)?.

4 0

4 years ago

An object is thrown upward with some velocity. If the object rises 77.5 m above the point of release, (a) how fast was the objec

jolli1 [7]

Answer:

$v_o=39\ m/s\\t_m=4\ s$

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

$\displaystyle h_m=H+\frac{v_o^2}{2g}$

The object referred to in the question is thrown from a height H=0 and the maximum height is hm=77.5 m.

(a)

To find the initial speed we solve for vo:

$\displaystyle v_o=\sqrt{2gh_m}$

$v_o=\sqrt{2\cdot 9.8\cdot 77.5}$

$v_o=39\ m/s$

(b)

The maximum time or the time taken by the object to reach its highest point is calculated as follows:

$\displaystyle t_m=\frac{v_o}{g}$

$\displaystyle t_m=\frac{39}{9.8}$

$t_m=4\ s$

7 0

3 years ago

Two negative charges that are both -3.0 C push each other apart with a force of 19.2 N. How far apart are the two charges ?

fgiga [73]

The Coulomb's force acting between two charges is
$F=k_e \frac{q_1 q_2}{r^2}$
where $k_e = 8.99 \cdot 10^9 N m^{-2}C^{-2}$ is the Coulomb's constant, q1 and q2 the two charges, and r the distance between them.

Using $q_1 = q_2 = -3 C$ , we can find the distance between the two charges when the force is F=19.2 N:
$r= \sqrt{k_e \frac{q_1 q_2}{F} }= \sqrt{ 8.99\cdot 10^9 \frac{(-3.0C)^2}{19.2 N} }=6.5 \cdot 10^4 m = 65 km$

5 0

3 years ago

What effect can distress have?

stiks02 [169]

Answer:

A constant feeling of pressure

4 0

3 years ago

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