Frequency - transferred through satellites and picked up through their receivers...
Answer:
4.9 cm
Explanation:
From Hook's Law,
F = ke......................... Equation 1
Where F= force, e = extension, k = spring constant.
Note: the Force acting on the the spring is the weight of the mass.
W = mg.
F = mg.................... Equation 2
Where m = mass, g = acceleration due to gravity
Substitute equation 2 into equation 1
mg = ke
make e the subject of the equation
e = mg/k............... Equation 3.
Given: m = 2 kg, g = 9.8 m/s², k = 400 N/m
e = (2×9.8)/400
e = 19.6/400
e = 0.049 m
e = 4.9 cm
Answer:
x ( t ) = F / 5.5 t²
Explanation:
acceleration dv / dt = F / 5.5
dv = F / 5.5 dt
integraring on both sides
v = F / 5.5 t + c
when t = 0 , v = 0
c = 0
v = F / 5.5 t
ds / dt = F / 5.5 t
integrating on both sides
s = F / 5.5 t² + c₁
when t = 0 , s = 0
c = 0
so
x ( t ) = F / 5.5 t²
This is the required relation.
<h2>
Hello!</h2>
The answer is:
The correct option is:
C. ![4.5x10^{3}N](https://tex.z-dn.net/?f=4.5x10%5E%7B3%7DN)
<h2>
Why?</h2>
To calculate the force exerted by the pump, we must remember the formula to calculate power, also, we must remember that power means work done in a determined period of time.
We have that power can be calculated by the following equation:
![Power(W)=F*V=N.\frac{m}{s}=\frac{N.m}{s}=1Watt](https://tex.z-dn.net/?f=Power%28W%29%3DF%2AV%3DN.%5Cfrac%7Bm%7D%7Bs%7D%3D%5Cfrac%7BN.m%7D%7Bs%7D%3D1Watt)
So, we are given the following information:
![Power=3.4x10^{2}W=340W=340\frac{N.m}{s}\\\\V=\frac{7.5x^{-2}m }{s}=\frac{0.075m}{s}](https://tex.z-dn.net/?f=Power%3D3.4x10%5E%7B2%7DW%3D340W%3D340%5Cfrac%7BN.m%7D%7Bs%7D%5C%5C%5C%5CV%3D%5Cfrac%7B7.5x%5E%7B-2%7Dm%20%7D%7Bs%7D%3D%5Cfrac%7B0.075m%7D%7Bs%7D)
Now, substituting and calculating we have:
![Power(W)=F*V](https://tex.z-dn.net/?f=Power%28W%29%3DF%2AV)
![340\frac{N.m}{s}=F*\frac{0.075m}{s}](https://tex.z-dn.net/?f=340%5Cfrac%7BN.m%7D%7Bs%7D%3DF%2A%5Cfrac%7B0.075m%7D%7Bs%7D)
![F=\frac{340\frac{N.m}{s}}{\frac{0.075m}{s}}=4,533N=4.5x10^{3}N](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B340%5Cfrac%7BN.m%7D%7Bs%7D%7D%7B%5Cfrac%7B0.075m%7D%7Bs%7D%7D%3D4%2C533N%3D4.5x10%5E%7B3%7DN)
Hence, the correct option is:
C. ![4.5x10^{3}N](https://tex.z-dn.net/?f=4.5x10%5E%7B3%7DN)
Have a nice day!
Answer:
a) actual reading=2mm+(0.1×8)=2.8 mm=0.28 cm
b)actual reading=5 mm+(0.1×7)=5.7mm=0.57 cm
c)actual reading=9 mm=0.9 cm
d)actual reading=0 mm+(0.1×7)=0.7 mm=0.07 cm
e)actual reading=19 mm+(0.1×9)=19.9 mm=1.99 cm
f)actual reading=15 mm+(0.1×3)=15.3 mm=1.53 cm
g)actual reading=11 mm(0.1×5)=11.5 mm=1.15 cm