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Snowcat [4.5K]
3 years ago
8

Consider the electric force between a pair of charged particles a certain

Physics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

Doubled

Explanation:

F = (kq1q2) / r^2

F and q (Either q1 or q2) are directly proportional, so double the charge would also double the electruc force between the charges.

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Your order is correct here.

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A shopper weighs 4.00 kg of apples on a supermarket scale whose spring obeys Hooke's law and notes that the spring stretches a d
Irina-Kira [14]

Answer:

a) 0.040625 m

b) 5.02272 J

Explanation:

k = Spring constant

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a)

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F=kx\\\Rightarrow x=\frac{F}{k}\\\Rightarrow x=\frac{6.5\times 9.81}{1569.6}\\\Rightarrow x=0.040625\ m

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W=\frac{1}{2}kx^2\\\Rightarrow W=\frac{1}{2}\times 1569.6\times 0.08^2\\\Rightarrow W=5.02272\ J

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3 years ago
a model rocket climbs 200 m in 4 seconds. if was moving 10 m/s to begin with, what is it’s final velocity?
artcher [175]
So first Identify all the given Varibales so u can choose which Eqauton to use

D=200m
T=4s
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Plug in the values

200= 0.50 (Vf+10) 4

Divide the 4 out of the right side and if you do sumthing to one side you gotta do it to the other

200 divided by 4= 0.50(Vf+10)
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Now expand the 0.50

So 50= 0.5Vf + 5 (because 0.5 times 10 is 5)

Now get rid of the 5

50-5= 0.5Vf

45 =0.5Vf now Divide the 0.5 out

45 divided by 0.5 = Vf

And 45/0.5 is 90

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