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Snowcat [4.5K]
3 years ago
8

Consider the electric force between a pair of charged particles a certain

Physics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

Doubled

Explanation:

F = (kq1q2) / r^2

F and q (Either q1 or q2) are directly proportional, so double the charge would also double the electruc force between the charges.

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A point charge is placed at the center of a spherical Gaussian surface. The electricflux ΦEischangedif(a) a second point charge
Simora [160]

Answer:

(b) the point charge is moved outside the sphere

Explanation:

Gauss' Law states that the electric flux of a closed surface is equal to the enclosed charge divided by permittivity of the medium.

\int\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

According to this law, any charge outside the surface has no effect at all. Therefore (a) is not correct.

If the point charge is moved off the center, the points on the surface close to the charge will have higher flux and the points further away from the charge will have lesser flux. But as a result, the total flux will not change, because the enclosed charge is the same.

Therefore, (c) and (d) is not correct, because the enclosed charge is unchanged.

7 0
4 years ago
In a diffraction grating experiment, light of 600 nm wavelength produces a first-order maximum 0.350 mm from the central maximum
NARA [144]

Answer:

497.143 nm.

Explanation:

Diffraction grating experiment is actually done by passing light through diffraction glasses, the passage of the light causes some patterns which can be seen on the screen. This is because light is a wave and it can spread.

The solution to the question is through the use of the formula in the equation (1) below;

Sin θ = m × λ. ---------------------------------(1).

Where m takes values from 0, 1, 2, ...(that is the diffraction grating principal maxima).

Also, m × λ = dc/ B -------------------------------------------(2).

We are to find the second wavelength, therefore;

λ2 =( m1/c1) × (c2/m2) × λ1 ------------------------(3).

Where c1 and c2 are the order maximum and m = order numbers. Hence;

λ2 = (1/ .350) × (.870/3) × 600 = 497.143 nm.

7 0
3 years ago
Read 2 more answers
You are asked to design a spring that will give a 1070 kg satellite a speed of 3.75 m/s relative to an orbiting space shuttle. Y
Dvinal [7]

Answer:

380697.33\ \text{N/m}

0.138\ \text{m}

Explanation:

m = Mass rocket = 1070 kg

v = Velocity of rocket = 3.75 m/s

a = Acceleration of rocket = 5g

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

The energy balance of the system is given by

\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\Rightarrow kx=\dfrac{mv^2}{x}\\\Rightarrow kx=\dfrac{1070\times 3.75^2}{x}\\\Rightarrow kx=\dfrac{7250}{x}

The force balance of the system is given by

ma=kx\\\Rightarrow m5g=\dfrac{7250}{x}\\\Rightarrow x=\dfrac{7250}{1070\times 5\times 9.81}\\\Rightarrow x=0.138\ \text{m}

The distance the spring must be compressed is 0.138\ \text{m}

k=\dfrac{7250}{x^2}\\\Rightarrow k=\dfrac{7250}{0.138^2}\\\Rightarrow k=380697.33\ \text{N/m}

The force constant of the spring is 380697.33\ \text{N/m}.

4 0
3 years ago
we measure a voltage difference of 5.0 V between two points on the conducting paper between two parallel conducting electrodes.
Alex17521 [72]

Answer:

E=1824.81 V/m

Explanation:

Given that

Voltage difference = 5 V

Distance ,D= 3 mm

 θ = 24°

As we know that electric filed given as

E=\dfrac{V}{d}

Given that D is 24° with respect to the perpendicular to the electrodes.So we have to take cos component of D.

d= D cosθ

d= 3 cos24°

d = 2.74 mm

So

E=\dfrac{V}{d}

E=\dfrac{5}{2.74\times 10^{-3}}

E=1824.81 V/m

8 0
3 years ago
What is the correct definition of solution?
STALIN [3.7K]

B.a homogeneous mixture

A solution is a homogeneous mixture of two or more substances. The amount of solute that can be dissolved in solvent is called its solubility.

4 0
3 years ago
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