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balu736 [363]
2 years ago
8

A water pump with a power of 3.4 × 102 watts lifts water at the rate of 7.5 × 10-2 meters/second from a water tank. What is the

force exerted by the pump on the water?
A.
1.5 × 103 newtons
B.
2.2 × 103 newtons
C.
4.5 × 103 newtons
D.
5.4 × 103 newtons
Physics
1 answer:
Neporo4naja [7]2 years ago
5 0
<h2>Hello!</h2>

The answer is:

The correct option is:

C. 4.5x10^{3}N

<h2>Why?</h2>

To calculate the force exerted by the pump, we must remember the formula to calculate power, also, we must remember that power means work done in a determined period of time.

We have that power can be calculated by the following equation:

Power(W)=F*V=N.\frac{m}{s}=\frac{N.m}{s}=1Watt

So, we are given the following information:

Power=3.4x10^{2}W=340W=340\frac{N.m}{s}\\\\V=\frac{7.5x^{-2}m }{s}=\frac{0.075m}{s}

Now, substituting and calculating we have:

Power(W)=F*V

340\frac{N.m}{s}=F*\frac{0.075m}{s}

F=\frac{340\frac{N.m}{s}}{\frac{0.075m}{s}}=4,533N=4.5x10^{3}N

Hence, the correct option is:

C. 4.5x10^{3}N

Have a nice day!

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Crazy boy [7]

Answer:

3125 N

Explanation:

diameter /2 =radius

so r1 =14cm , r2 =35cm

f1/A1 =f2/A2.

f2 = f1 × A2 / A1

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f2 =3125N

4 0
3 years ago
A motorist driving at 25 meters/second decelerates to
Ilia_Sergeevich [38]
Work done = 0.5*m*[(v2)^2 - (v1)^2]
where m is mass,
v2 and v1 are the velocities.

Given that m = 1.50 x 10^3 kg, v2 = -15 m/s (decelerates), v1 = 25 kg,

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Just ignore the negative value for the final result because work is a scalar quantity.
8 0
3 years ago
Read 2 more answers
Options are:<br>a)4Cn<br>b)5Cn<br>c)6 Cn<br>d)3 Cn<br>​
nasty-shy [4]

Answer:

Option B. 5 nC

Explanation:

From the question given above, the following data were obtained:

Capicitance (C) = 100 pF

Potential difference (V) = 50 V

Quantity of charge (Q) =?

Next, we shall convert 100 pF to Farad (F). This can be obtained as follow:

1 pF = 1×10¯¹² F

Therefore,

100 pF = 100 pF × 1×10¯¹² F / 1 pF

100 pF = 1×10¯¹⁰ F

Next, we shall determine the quantity of charge. This can be obtained as follow:

Capicitance (C) = 1×10¯¹⁰ F

Potential difference (V) = 50 V

Quantity of charge (Q) =?

Q = CV

Q = 1×10¯¹⁰ × 50

Q = 5×10¯⁹ C

Finally, we shall convert 5×10¯⁹ C to nano coulomb (nC). This can be obtained as follow:

1 C = 1×10⁹ nC

Therefore,

5×10¯⁹ C = 5×10¯⁹ C × 1×10⁹ nC / 1 C

5×10¯⁹ C = 5 nC

Thus, the quantity of charge is 5 nC

3 0
2 years ago
How is work calculated?
BartSMP [9]

Work is force times distance. If there's no distance, there's no work being done.

6 0
3 years ago
Is it true weather refers to the conditions of the atmosphere at a given time and place
damaskus [11]

yes that is true because climate is over a period of time


8 0
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