Answer:
V’/V= 1.05
Explanation:
The density is defined with the ratio of the mass to the volume, for the fish with the collapsed sack
ρ₁ = m / V
The density of the fish with the bag full of air is
ρ₂ = m / V’
For the fish to float if it exerts its density must be exactly equal to that of the surrounding water
We clear the mass and match
m = ρ1 V = ρ2 V'
ρ₁ V = ρ₂ V’
V ’/ V = ρ₁ / ρ₂
V ’/ V = 1.05 / 1
V ’= 1.05 V
This is that the fish should increase its volume by 5%
"Celestial" = anything to do with the sky
("Cielo" ..... Spanish for "sky"
"Ceiling" ... that thing up over your head
"Caelum" .. Latin for "heaven")
"Terrestrial" = anything to do with the Earth
("Terra" ... Latin for "Earth")
Answer:
6.05 cm
Explanation:
The given equation is
2 aₓ(x-x₀)=( Vₓ²-V₀ₓ²)
The initial head velocity V₀ₓ =11 m/s
The final head velocity Vₓ is 0
The accelerationis given by =1000 m/s²
the stopping distance = x-x₀=?
So we can wind the stopping distance by following formula
2 (-1000)(x-x₀)=[
]
x-x₀=6.05*
m
=6.05 cm
