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krek1111 [17]
3 years ago
11

If you placed a negatively charged object within this electric field, which direction will it move?

Physics
2 answers:
kramer3 years ago
6 0
Option A would be the right answer.
Alex787 [66]3 years ago
4 0

Answer: Option (A) to the right

Explanation:

Let me explain it in simple words!

Always remember that the electric field direction is outward from a positive charge (be it a single positively charged particle, or a positive rod) and inward into a negative charge. In this case, as you can see, the electric field arrows' direction is from right to left. It means that the positive charge is on the right side, and the negative charge is on the left side.

Now what will happen when you place a negatively charged object within this electric field? Well, as you know, two negatively charged objects repel each other, and positively and negatively charged objects attract each other. The negatively charged object will move<em> towards right</em>, since there is a positive charge on right side (as explained in the first paragraph), which will attract this negatively charged object. Furthermore, the negative charge on the left side will repel this negatively charged object towards right (against the direction of the electric field). Hence, the correct answer is Option (A) to the right.

You must be wondering why I didn't mention the upward and downward motion. Well, again always remember that the positively charged object moves along the direction of electric field, and the negatively charged object moves against the direction of electric field (as explained above). <em>Charged bodies do not move perpendicular to the direction of electric field</em> (unless there is some net external force applied to that object).

I hope this helps! :)

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The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.

<h3>What mass of lead should be placed on the cube?</h3>

Given: Side of the cube (a) = 20cm

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ρcgV = ρg × (Ax)

Substituting the values in the above equation, we get

(650*(0.2 m)^3)=1000*(0.2 m)^2*x

x = 0.13

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$$A = a^2 is the area of the cross-section

ρ is the density of the water

V is the volume of the cube

Now, the height above the surface of the water would be

h = a − x

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h = 0.2 − 0.13

h = 0.07 m

b) The mass added is "m" so the complete cube is submerged in the water, therefore

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The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.

To learn more about buoyant force refer to:

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Explanation:

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a ray of light incident on a mirror, at an angle of 45°. Another mirror is placed at an angle of 45° to the first ones as shown.
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Answer:

If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)

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A swimmer is swimming to the left with a speed of 1.0 m/s when she starts to speed up with constant acceleration. The swimmer re
kolezko [41]

Answer:

Correct answer: t = 2.86 seconds

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We will calculate the acceleration from this formula

a = (V² - V₀²) / (2 d) = (2.5² - 1²) / (2 · 5) = (6.25 - 1) / 10 = 5.25 / 10

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then we use this formula

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Answer:

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\tau=\tau_t+\tau_f\\\Rightarrow \tau=0.021125+0.021125\\\Rightarrow \tau=0.04225\ Nm

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