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krek1111 [17]
3 years ago
11

If you placed a negatively charged object within this electric field, which direction will it move?

Physics
2 answers:
kramer3 years ago
6 0
Option A would be the right answer.
Alex787 [66]3 years ago
4 0

Answer: Option (A) to the right

Explanation:

Let me explain it in simple words!

Always remember that the electric field direction is outward from a positive charge (be it a single positively charged particle, or a positive rod) and inward into a negative charge. In this case, as you can see, the electric field arrows' direction is from right to left. It means that the positive charge is on the right side, and the negative charge is on the left side.

Now what will happen when you place a negatively charged object within this electric field? Well, as you know, two negatively charged objects repel each other, and positively and negatively charged objects attract each other. The negatively charged object will move<em> towards right</em>, since there is a positive charge on right side (as explained in the first paragraph), which will attract this negatively charged object. Furthermore, the negative charge on the left side will repel this negatively charged object towards right (against the direction of the electric field). Hence, the correct answer is Option (A) to the right.

You must be wondering why I didn't mention the upward and downward motion. Well, again always remember that the positively charged object moves along the direction of electric field, and the negatively charged object moves against the direction of electric field (as explained above). <em>Charged bodies do not move perpendicular to the direction of electric field</em> (unless there is some net external force applied to that object).

I hope this helps! :)

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For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is
ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)

where A(t)=A₀e^{\frac{-bt}{2m}}

 A₀ is the amplitude at t=0 and

w' is the angular frequency of damped SHM, which is given by,

w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

Now coming to the problem,

Given: m=1.2 kg

           k=9.8 N/m

           b=210 g/s= 0.21 kg/s

           A₀=13 cm

a) A(t)=A₀/8

⇒A₀e^{\frac{-bt}{2m}} =A₀/8

⇒e^{\frac{bt}{2m}}=8

applying logarithm on both sides

⇒\frac{bt}{2m}=ln(8)

⇒t=\frac{2m*ln(8)}{b}

substituting the values

t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)

b) w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}

T'=\frac{2\pi}{w'}, where T' is time period of damped SHM

⇒T'=\frac{2\pi}{2.86}=2.2s

let n be number of oscillations made

then, nT'=t

⇒n=\frac{24}{2.2}=11(approx)

8 0
3 years ago
In three sentences, please describe SIMPLE HARMONIC motion, and give two examples. Thank you! :-)
11Alexandr11 [23.1K]
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3 0
3 years ago
What is the period of a wave that has a frequency of 300 hz?
Butoxors [25]

Answer:

T = 0.003 s

(Period is written as T)

Explanation:

Period = time it takes for one wave to pass (measured in seconds)

frequency = number of cycles that occur in 1 second

(measured in Hz / hertz / 1 second)

Period : T

frequency : f

So, if we know that the frequency of a wave is 300 Hz, we can find the period of the wave from the relation between frequency and period

T =  \frac{1}{f}    f = \frac{1}{T}

to find the period (T) of this wave, we need to plug in the frequency (f) of 300

T = \frac{1}{300}

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So, the period of a wave that has a frequency of 300 Hz is 0.003 s

[the period/T of this wave is 0.003 s]

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tino4ka555 [31]
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3 years ago
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mote1985 [20]

The time  taken for anna to move the box the distance of 9.72 meters is 25.9 seconds. The correct option is c.

<h3>What is force?</h3>

The force is the action of push or pull to move or stop an object.

Anna pushes a box with a force of 8.00 newtons. she generates a power of 3.00 watts.

Force is related to power by the relation

Force = Power / Velocity

Put the values, we get

8 = 3/V

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Velocity is defined as the ratio of distance and the time taken.

The box is moved by the distance of 9.72 meters. So, time taken is

V = d/t

0.375 = 9.72/t

t =25.9 seconds.

Thus,  time  taken for anna to move the box the distance of 9.72 meters is 25.9 seconds.

Learn more about force.

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7 0
1 year ago
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