All categories

4 years ago

If you placed a negatively charged object within this electric field, which direction will it move?

Physics

2 answers:

kramer4 years ago

6 0

Option A would be the right answer.

Alex787 [66]4 years ago

4 0

Answer: Option (A) to the right

Explanation:

Let me explain it in simple words!

Always remember that the electric field direction is outward from a positive charge (be it a single positively charged particle, or a positive rod) and inward into a negative charge. In this case, as you can see, the electric field arrows' direction is from right to left. It means that the positive charge is on the right side, and the negative charge is on the left side.

Now what will happen when you place a negatively charged object within this electric field? Well, as you know, two negatively charged objects repel each other, and positively and negatively charged objects attract each other. The negatively charged object will move<em> towards right</em>, since there is a positive charge on right side (as explained in the first paragraph), which will attract this negatively charged object. Furthermore, the negative charge on the left side will repel this negatively charged object towards right (against the direction of the electric field). Hence, the correct answer is Option (A) to the right.

You must be wondering why I didn't mention the upward and downward motion. Well, again always remember that the positively charged object moves along the direction of electric field, and the negatively charged object moves against the direction of electric field (as explained above). <em>Charged bodies do not move perpendicular to the direction of electric field</em> (unless there is some net external force applied to that object).

I hope this helps! :)

You might be interested in

A ball is thrown at an angle of to the ground. If the ball lands 90 m away, what was the initial speed of the ball?

andre [41]

Answer:

The initial speed of the ball is 30 m/s.

Explanation:

It can be assumed that the ball is thrown at an angle of 45 degrees to the ground. The ball lands 90 m away. We need to find the initial speed of the ball. We know that the horizontal distance covered by the projectile is called its range. It is given by :

$R=\dfrac{u^2\ sin2\theta}{g}$

u is the initial speed of the ball.

$v=\sqrt{\dfrac{Rg}{sin2\theta}}$

$v=\sqrt{\dfrac{90\times 9.8}{sin2(45)}}$

v = 29.69 m/s

v = 30 m/s

So, the initial speed of the ball is 30 m/s. Hence, this is the required solution.

8 0

3 years ago

In an "atom smasher," two particles collide head on at relativistic speeds. If the velocity of the first particle is 0.741c to t

galina1969 [7]

Answer:

$W_x = 0.9156\ c$

Explanation:

given,

velocity of particle 1 = 0.741 c to left

velocity of second particle = 0.543 c to right

relative velocity between the particle = ?

for the relative velocity calculation we have formula

$W_x = \dfrac{|u_x - v_x|}{1-\dfrac{u_xv_x}{c^2}}$

u_x = 0.543 c

v_x = - 0.741 c

$W_x = \dfrac{0.543 c - (-0.741 c)}{1-\dfrac{(0.543 c)(-0.741 c)}{c^2}}$

$W_x = \dfrac{0.543 c +0.741 c)}{1+\dfrac{(0.543)(0.741)c^2}{c^2}}$

$W_x = \dfrac{1.284c}{1+0.402363}$

$W_x = 0.9156\ c$

Relative velocity of the particle is $W_x = 0.9156\ c$

5 0

3 years ago

Examples of energy balance: physical education

mart [117]

Answer:children burn calories to being a student

Explanation:That mean when a children getting ready to go to high school

7 0

3 years ago

The graph below shows the velocity of a car over time.

jekas [21]

Answer:

D. Calculate the area under the graph.

Explanation:

The distance made during a particular period of time is calculated as (distance in m) = (velocity in m/s) * (time in s)

You can think of such a calculation as determining the area of a rectangle whose sides are velocity and time period. If you make the time period very very small, the rectangle will become a narrow "bar" - a bar with height determined by the average velocity during that corresponding short period of time. The area is, again, the distance made during that time. Now, you can cover the entire area under the curve using such narrow bars. Their areas adds up, approximately, to the total distance made over the entire span of motion. From this you can already see why the answer D is the correct one.

Going even further, one can make the rectangular bars arbitrarily narrow and cover the area under the curve with more and more of these. In fact, in the limit, this is something called a Riemann sum and leads to the definition of the Riemann integral. Using calculus, the area under a curve (hence the distance in this case) can be calculated precisely, under certain existence criteria.

3 0

4 years ago

Read 2 more answers

A steel cable has a cross-sectional area 2.54 10-3 m2 and is kept under a tension of 1.01 104 N. The density of steel is 7860 kg

ElenaW [278]

Answer:

The speed is equals to 22.49 m/s

Explanation:

Given Data:

$Area = A=2.54*10^-^3m^2\\Force = F = 1.01*10^4N\\density = p = 7860 kg/m^3$