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3 years ago

What is centripetal force that allows a car to move around a sharp curve in a roadway?

1 answer:

7 0

The centripetal force that allows a car to move around a sharp curve in a roadway is the frictional force between the tires of its wheels and the surface of the road.

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what will be the effect on the acceleration due to gravity of the earth if it is compressed to a the size the moon?

GuDViN [60]

Answer:

it gravitional pull on earth will increased becauste it is compress to a form of moon which is comperatively smaller so the gravitonal pull on per cm of earth will incrased so we can say that there will be change in acceleration due to gravity

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3 years ago

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Find the x-component of this vector: 47.3 m 39.4 ° Remember, angles are measured from the + x axis. x-component (m)

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The answer to this question is 86.7

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4 years ago

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A 77 kg student traveling in a car with a constant velocity has a kinetic energy of 1.7 104 J. What is the speedometer reading o

AVprozaik [17]

ANSWER

75.65 km/h

EXPLANATION

Given:

• The student's mass, m = 77 kg

• The kinetic energy of the student in the car, KE = 1.7 x 10⁴ J

Find:

• The speed read in the speedometer of the car, which is the speed of the student, v (in km/h)

The kinetic energy of an object with mass m, traveling at a speed v, is,

$KE=\frac{1}{2}mv^2$

Solving for v,

$v=\sqrt{\frac{2KE}{m}}$

Replace the known values and solve,

$v=\sqrt{\frac{2\cdot1.7\cdot10^4J}{77kg}}\approx21.013m/s$

Note that because the kinetic energy is given in Joules - which is equivalent to kg*m²/s², the speed we found is in m/s. Now, knowing that there are 3600 seconds in 1 hour and that 1 km is equivalent to 1000 m, we can convert this to km/s,

$v=21.013\frac{m}{s}\cdot\frac{3600s}{1h}\cdot\frac{1km}{1000m}\approx75.65km/h$

Hence, the speedometer reading of the car is 75.65 km/h, rounded to the nearest hundredth.

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2 years ago

Why is training important?

stira [4]

So you work hard and you do well i’m getting good grades or doing something better.

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3 years ago

Boxes A and B are being pulled to the right on a frictionless surface. Box A has a larger mass than B. How do the two tension fo

Vlad1618 [11]

Answer:

Tension T1 is less than tension T2.

T1 < T2

Explanation:

According to given data,

mass of box A ( mA) is grater than mass of box B (mB)

we can write,

m(A) > m(B)

Newton's second law states that:

Tension of object is directly proportional to the mass of the system.

T ∝ m

here Boxes A and B are being pulled to the right on a frictionless surface,

so Tension T1 generates due to the mass of box A m(A)

and Tension T2 arises due to mass of the system m(A) + m(B)

Thus tension T1 will be less than tension T2

T1 < T2

learn more about Tension force here:

brainly.com/question/13175014

#SPJ4

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2 years ago