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2 years ago

9

What is centripetal force that allows a car to move around a sharp curve in a roadway?

1 answer:

Ulleksa [173]2 years ago

7 0

<span> The centripetal force that allows a car to move around a sharp curve in a roadway is the frictional force between the tires of its wheels and the surface of the road. </span>

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If two variables have a non-related relationship and one of the variables is changed, how will the other variable change?

PolarNik [594]

If one of the variables is changed, that tells nothing about what happens to the other one, or IF anything happens, or when, or how long it lasts. Because they are UN-RELATED. You just said so yourself.

None of the choices says this.

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3 years ago

A boy pushes forward a cart of groceries with a total mass of 40.0 kg. What is the acceleration of the cart if the net force on

melisa1 [442]

1.5m/s2

F=ma

a=F/m

a=60/40

a=1.5m/s2

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3 years ago

Please help ASAP!!

bixtya [17]

There is kinetic energy when it is sitting at the top, then as it goes towards the bottom, the kinetic energy is transformed into potential energy.

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3 years ago

On the surface of the earth the weight of an object is 200 lb. Determine the height of the

siniylev [52]

Answer:

The height of the object is 5007.4 miles.

Explanation:

Given that,

Weight of object = 200 lb

We need to calculate the value of $Gmm_{e}$

Using formula of gravitational force

$F=\dfrac{Gmm_{e}}{r^2}$

Put the value into the formula

$200=\dfrac{Gmm_{e}}{(3958.756)^2}$

$200\times(3958.756)^2=Gmm_{e}$

$Gmm_{e}=3.134\times10^{9}$

We need to calculate the height of the object

Using formula of gravitational force

$F=\dfrac{Gmm_{e}}{r^2}$

Put the value into the formula

$125=\dfrac{200\times(3958.756)^2}{r^2}$

$r^2=\dfrac{200\times(3958.756)^2}{125}$

$r^2=25074798.5$

$r=\sqrt{25074798.5}$

$r=5007.4\ miles$

Hence. The height of the object is 5007.4 miles.

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3 years ago

Please help. <br><br> Which describe colloids? Check all that apply.

rewona [7]

A) heterogeneous mixture & I believe B?

I know A is correct though

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2 years ago