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4 years ago

What is the correct value using 3 significant figures for 14.8232 g/mol?

Chemistry

1 answer:

REY [17]4 years ago

5 0

Answer:

14.8 g/mol

Explanation:

Starting on the left, count in 3 numbers (14.8), then round using the next number (0.02).

Because 2 is less than 5, the number stays the same and is not rounded up.

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How many Hydrogen (H) atoms are in the Chemical Formula(C2H2O2)2?

Lelechka [254]

Answer:

Explanation:

in (C2H2O2)2 there are 4 hydrogen atoms

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3 years ago

Is N2F5 ionic or covalent

Ulleksa [173]

Answer:

it's a covalent compound

Explanation:

Two non metals are bonded to together

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3 years ago

The rapid decomposition of sodium azide, NaN3, to its elements is one of the reactions used to inflate airbags: 2 NaN3 (s)  2 N

masha68 [24]

<u>Answer:</u> The amount of nitrogen gas produced is 3.864 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $NaN_3$ = 6.00 g

Molar mass of $NaN_3$ = 65 g/mol

Putting values in equation 1, we get:

$\text{Moles of }NaN_3=\frac{6.00g}{65g/mol}=0.092mol$

For the given chemical reaction:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

By Stoichiometry of the reaction:

2 moles of $NaN_3$ produces 3 moles of nitrogen gas

So, 0.092 moles of $NaN_3$ will produce = $\frac{3}{2}\times 0.092=0.138mol$ of nitrogen gas

Now, calculating the mass of nitrogen gas by using equation 1, we get:

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.138 moles

Putting values in equation 1, we get:

$0.138mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.138mol\times 28g/mol)=3.864g$

Hence, the amount of nitrogen gas produced is 3.864 grams

7 0

3 years ago

What mass of sodium oxalate na2c2o4 is needed to prepare 0.250 l of a 0.100 m solution?

Lena [83]

Molarity = number of moles of solute / liters of solution
number of moles = molarity * liters of solution
number of moles of Na2C2O4 = 0.1 * 0.25 = 0.025 moles

Now, from the periodic table:
mass of Na = 22.9 grams
mass of C = 12 grams
mass of O = 16 grams
molar mass of Na2C2O4 = 2(22.9) + 2(12) + 4(16) = 133.8 grams
Therefore, one mole is equal to 133.8 grams. To know the mass of 0.025 moles, all you have to do is cross multiplication as follows:
mass = (0.025*133.8) / 1 = 3.345 grams

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3 years ago

Read 2 more answers

What minimum energy is required to excite a vibration in HCl?

VMariaS [17]

Answer:

8.85 × 101 ^ 13 S^-1

Explanation:

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7 0

3 years ago