What is the correct value using 3 significant figures for 14.8232 g/mol?
1 answer:
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Answer : The correct option is, (b) +115 J/mol.K
Explanation :
Formula used :
where,
= change in entropy
= change in enthalpy of vaporization = 40.5 kJ/mol
= boiling point temperature = 352 K
Now put all the given values in the above formula, we get:
Therefore, the standard entropy of vaporization of ethanol at its boiling point is +115 J/mol.K
Answer:
pH = 2.03
Explanation:
The pH can be calculated using the following equation:
(1)
The concentration of H₃O⁺ is calculated using the dissociation constant of the next reaction:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺
1.00 M
Solving the above equation for H₃O⁺, we have:
(2)
The dissociation constant is equal to:
Now, by solving the equation of the solubility product for Herbigon, we can find [CH₃COO⁻]:
CH₃COOX ⇄ CH₃COO⁻ + X⁺
5.00x10⁻³ M
By entering the values of [CH₃COO⁻] and Ka, into equation (2) we can calculate [H₃O⁺]:
Hence, the pH is:
Therefore, the pH must be 2.03 to yield a solution in which the concentration of X⁺ is 5.00x10⁻³M.
I hope it helps you!
Answer:
Total number of water molecules produced after the reaction is 1.956×10^22 molecules of water.
Explanation:
By the reaction
H2+ 1/2 O2 → H2O
Moles of O2 = 5.2\32
⇒1 mole of O2 produce 1 mole of H2O
1 mole O2 will produce 2 mole of H2O
Therefore, 5.2\32 mole will produce
⇒ Molecules of H2O will be
=
= 1.956×10^22 moleculesof H2O.