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4 years ago

Question 10 of 25

Chemistry

2 answers:

konstantin123 [22]4 years ago

8 0

Answer:

Option D. 20.6 N

Explanation:

From the question,

m = 2.1Kg

g = 9.8m/s2

The normal force acting on the jar = mg = 2.1 x 9.8 = 20.6N

alukav5142 [94]4 years ago

6 0

D is the answer and I think you will pass whatever assignment you r doing

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Orlov [11]

Answer:

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3 years ago

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Nadusha1986 [10]

Answer:

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Diffusion and Osmosis

Explanation:

found this online. hope this helps

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3 years ago

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Your friend looks at a piece of ice and says “Solids, like ice, have a fixed shape because the particles are not moving.” Is you

Alex_Xolod [135]

Answer:

yes

Explanation:

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3 years ago

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PLSSSSS HELP I DONT GET THIS PROBLEMMMM

Aleks [24]

Answer:

C. 7370 joules.

Explanation:

There is a mistake in the statement. Correct form is described below:

<em>Using the above data table and graph, calculate the total energy in Joules required to raise the temperature of 15 grams of ice at -5.00 °C to water at 35 °C. </em>

The total energy needed to raise the temperature is the combination of latent and sensible heats, all measured in joules, and represented by the following model:

$Q = m\cdot [c_{i} \cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})]$ (1)

Where:

$m$ - Mass of the sample, in grams.

$c_{i}$ - Specific heat of ice, in joules per gram-degree Celsius.

$c_{w}$ - Specific heat of water, in joules per gram-degree Celsius.

$L_{f}$ - Latent heat of fusion, in joules per gram.

$T_{1}$ - Initial temperature of the sample, in degrees Celsius.

$T_{2}$ - Melting point of water, in degrees Celsius.

$T_{3}$ - Final temperature of water, in degrees Celsius.

$Q$ - Total energy, in joules.

If we know that $m = 15\,g$ , $c_{i} = 2.06\,\frac{J}{g\cdot ^{\circ}C}$ , $c_{w} = 4.184\,\frac{J}{g\cdot ^{\circ}C}$ , $L_{f} = 334.72\,\frac{J}{g}$ , $T_{1} = -5\,^{\circ}C$ , $T_{2} = 0\,^{\circ}C$ and $T_{3} = 35\,^{\circ}C$ , then the final energy to raise the temperature of the sample is:

$Q = (15\,g)\cdot \left[\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (5\,^{\circ}C)+ 334.72\,\frac{J}{g} + \left(4.184\,\frac{J}{g\cdot ^{\circ}C}\right)\cdot (35\,^{\circ}C) \right]$

$Q = 7371.9\,J$

Hence, the correct answer is C.

8 0

3 years ago

N2H4 + N2O4 --> N2 + H2O

givi [52]

Answer:

Explanation:

Since this problem is incomplete, let us give a simple explanation to solve it.

In any reaction, we always have reactants that are in short supply and those that are in excess.

A reactant in short supply in a reaction is called the limiting reagent. This reactant will usually determine the extent of the reaction. When it is used up, the reaction will stop and will not proceed further.

To solve for the limiting reagent, convert the given mass to number of moles. Always work with number of moles.

Then write the balanced reaction equation.

Compare the moles from the balanced equation to that obtained. The reacting specie that is lesser in proportion is the limiting reagent

To solve the second part;

Compare the number of moles of the limiting reactant to that of the product i.e H₂O;

Use this number of moles to find mass;

Mass of H₂O = number of moles x molar mass

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3 years ago