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Marysya12 [62]
4 years ago
5

6) When a teacher counted her students in groups of 4, there were 2 students left over. When she counted them in groups of 5, sh

e had 1 student left over. If 15 of her students were girls, and she had more girls than boys, how many students did she have??
This needs to be shown full work for full credit on my college math class I need help it’s due this Wednesday!!!
Mathematics
1 answer:
sammy [17]4 years ago
3 0

Answer:

The solution is that there are 26 students in her class

Step-by-step explanation:

We know that 15 of her student are girls, and since there are more girls than boys in the class, there can at most be 15+14= 29 students in her class.

We need to find a number x between 16 (in the case where there is only one boy in the class) and 29, for which x/4 gives a remainder of 2, and x/5 gives a remainder of 1.

The numbers between 16 and 29, which when divided by 4 gives a remainder of 2 are:

18, 22, and 26

You can check yourself that these give a remainder of 2.

So it is one of these numbers. But the solution must also fulfill that the number divided by 5 gives a remainder of 1.

18/5 = 15 + remainder=3

22/5 = 4 + remainder=2

26/5 = 5 + remainder=1

Thus the only possible solution is 26.

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C - x < -6 and x < 2

Step-by-step explanation:

2x ">" -12 and 7x < 14. with negative numbers, the bigger the number the less it is. -12 < -6 because negative numbers work the opposite way that positive numbers do. I hope this helps you!!!!

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Step-by-step explanation:

first convert them to decimals

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3 years ago
Jasmine and Olivia each have a bracelet collection.
kobusy [5.1K]

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4 0
3 years ago
Read 2 more answers
Emily ran her first lap in 75 seconds she ran her second lap in 69 seconds using percentages how much better was her second lap
julsineya [31]

Answer:

Her second lap was <u>8%</u> better when compared to her first lap.

Step-by-step explanation:

Given:

Emily ran her first lap in 75 seconds she ran her second lap in 69 seconds.

Now, to find how much better was her second lap when compared to her first lap.

Emily ran her first lap in 75 seconds.

Emily ran her second lap in 69 seconds.

So, we get the difference in seconds:

75-69=6\ seconds.

<u><em>Thus, in her second lap she was 6 seconds better than first.</em></u>

Now, to get the percentage of her first lap better than second:

\frac{6}{75}\times 100

=0.08\times 100

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Therefore, her second lap was 8% better when compared to her first lap.

7 0
3 years ago
Can someone please help with #16
ollegr [7]

Answer:

∠ WZX = 50°

XW is not an altitude.

Step-by-step explanation:

16. See the attached figure.

XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ

Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13

Hence, ∠ YXZ = 2 ∠ WXY

⇒ 8x + 34 = 2(10x - 13)

⇒ 8x + 34 = 20x - 26

⇒ 12x = 60

⇒ x = 5.

Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)

Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°

Hence, from Δ WXZ,

∠ WZX + ∠ WXZ + ∠ XWZ = 180°

⇒ 50° + 37° + ∠ XWZ = 180°

⇒ ∠ XWZ = 93° ≠ 90°

Hence, XW is not an altitude. (Answer)

6 0
3 years ago
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