Answer:
The correct answer is c. 3/16.
Explanation:
In the given question two traits being studied, the traits are flower color and seed shape.
This is a typical Mendel’s dihybrid cross. According to the question purple colour (P) and round seed (R) are dominant traits.
When heterozygous purple-flowered (Pp), round-seeded (Rr) individuals are crossed, four different types of plants are produced phenotypically in the ratio 9:3:3:1.Out of 16 offspring, 9 are purple flowered, round seeded pea plants, 3 pea plants are white-flower with round seed, 3 are purple- flower with wrinkled seed and 1 pea plant is white-flowered with wrinkled seed pea plant is produced.
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Answer:
The correct answer is - option C.
Explanation:
CFTR is a short form of cystic fibrosis transmembrane conductance regulator protein which is caused by a recessive mutation in this protein. This mutation results in the accumulation of mucus in secretory organs.
As the disease is a recessive disease, for the mutant phenotype to expressed both copies of the allele required to be recessive.
The mother is negative for the CFTR. Hence, she will not transfer the mutant allele to her child So, the child would have a wild-type phenotype even if the father having two copies of recessive allele.
Thus, the correct answer is - option C.
Non living things like mountains,oxygen,water.etc
It should be 322.15. Hope it helps :)
