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Alecsey [184]
3 years ago
12

I need help. Will mark brainliest

Chemistry
2 answers:
Ugo [173]3 years ago
8 0

Answer:

17. HC₂H₃O₂ + H₂O  ⇄  C₂H₃O₂⁻  +  H₃O⁺       Ka

          A             B             CB             CA              

18. H₂SO₄ + 2H₂O →  2H₃O⁺  +  SO₄⁻²

         A           B            CA           CB          

19. CO₃⁻² + H₂O ⇄  HCO₃⁻  +  OH⁻      Kb

      B             A          AC          BC  

20.  HCO₃⁻  + NH₃  ⇄  CO₃⁻²  +  NH₄⁺       Ka

           A           B           BC           AC

21.   NH₄⁺ + OH⁻   ⇄   NH₃  +  H₂O     Ka

         A         B            BC        AC  

Explanation:

The acetic acid release a proton to water, to produce acetate and hydronium.

This is a weak acid.

The sulfuric acid release 2 protons to water to produce sulfate and hydronium.

This acid is considered as strong, but it is only strong in the first dissociation. The second dissociation is weak, with a Ka.

Carbonate takes a proton from water, to become bicarbonate (In this case, the carbonate behaves as a base).

Bicarbonate release a proton to ammonia, to make ammonium and carbonate anion.

Amonium cation release a proton to the hydroxide to make ammonia and water.

exis [7]3 years ago
5 0

Answer:

See explanation

Explanation:

Step 1: Data given

Bronsted-Lowry says the following:

Acid dissociation: HX + H2O → H3O+ + X-

Base dissociation: B + H2O → OH- + HB+

HC2H3O2 + H2O →

HC2HO2 is acetic acid, it's a weak acid. (CH3COOH)

This will be following the reaction HX + H2O → H3O+ + X-

CH3COOH + H2O → CH3COO- + H3O+

H2SO4 + H2O →

H2SO4 is a strong acid

This will be following the reaction HX + H2O → H3O+ + X-

H2SO4 + H2O → HSO4- + H3O+

CO3^2- + H2O →

CO3^2_ is a conjugate base

This will be following the reaction B + H2O → OH_ + HB+

CO3^2- + H2O → HCO3- + OH-

HCO3- + NH3 →

HCO3- (known as bicarbonate) is the conjugate base of H2CO3, a weak acid, and the conjugate acid of the carbonate ion.

NH3 is a weak base

HCO3- + NH3 → CO3^2- + NH4+

NH4+ + OH- →

The hydrogen on the ammonium ion (NH4+) can go back to the hydroxide ion (OH-) to form NH3 and H2O (ammonia and water) again. In this case, because the ammonium ion is donating a proton, it is called a conjugate acid.

NH4+ + OH- → NH3 + H2O

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Answer is "<span>the oxidizing agent receives electrons from the reducing agent</span><span>".

There are two types of reactants in redox reactions. One is oxidizing agent and other is reducing agent.

Oxidizing agent is a substance which helps to oxidize other substance by gaining electrons. This is also called as oxidizer. Due to the gaining electrons, oxidizing agents tend to be reduced.

Reducing agent or reducer helps to reduce other substance while loosening electrons. Hence, reducing agents tend to be oxidized.</span>

5 0
4 years ago
Plz solve mcqs#04 with full detailed.note
Sholpan [36]

Answer:

The correct option is;

(B) 1 s², 2s², 2p⁶, 3s², 3p³

Explanation:

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8 0
3 years ago
what mass of sodium chloride is produced when chlorine gas reacts with 0.29 grams of sodium iodide? working on stoichiometry and
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CI2 + 2Nal ---> 2NalCI + I2
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When bsia is assembled as an octamer, what is most likely to be true regarding l76, l77, and l79?
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<h3>What is entropic penalty?</h3>

The entropic penalty in regards to ordered water is known to be one that tells or account  for any form of  weaker binding of the antibiotic novobiocin to what we call resistant mutant of DNA gyrase.

Note that in regards to the scenario above, the Entropic penalty is seen as the thermodynamically disfavored needs that is required in forming a cage of polar solvent molecules that is known to be seen around surface that has exposed hydrophobic potion of a molecule.

Hence, The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

Learn more about octamer from

brainly.com/question/13198179

#SPJ1

See full question below

When Bs1A is assembled as an octamer, what is most likely to be true regarding L76, L77, and L79?

A. They are oriented toward the solvent-exposed exterior of the protein assembly.

B. The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

C. Unlike in a monomer, they are not situated within the hydrophobic cap.

D. Their physiochemical properties are not substantially dependent on their hydrophobicity

5 0
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liberstina [14]
#3- atoms remain bonded to each other in physical changes.
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