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Alecsey [184]
3 years ago
12

I need help. Will mark brainliest

Chemistry
2 answers:
Ugo [173]3 years ago
8 0

Answer:

17. HC₂H₃O₂ + H₂O  ⇄  C₂H₃O₂⁻  +  H₃O⁺       Ka

          A             B             CB             CA              

18. H₂SO₄ + 2H₂O →  2H₃O⁺  +  SO₄⁻²

         A           B            CA           CB          

19. CO₃⁻² + H₂O ⇄  HCO₃⁻  +  OH⁻      Kb

      B             A          AC          BC  

20.  HCO₃⁻  + NH₃  ⇄  CO₃⁻²  +  NH₄⁺       Ka

           A           B           BC           AC

21.   NH₄⁺ + OH⁻   ⇄   NH₃  +  H₂O     Ka

         A         B            BC        AC  

Explanation:

The acetic acid release a proton to water, to produce acetate and hydronium.

This is a weak acid.

The sulfuric acid release 2 protons to water to produce sulfate and hydronium.

This acid is considered as strong, but it is only strong in the first dissociation. The second dissociation is weak, with a Ka.

Carbonate takes a proton from water, to become bicarbonate (In this case, the carbonate behaves as a base).

Bicarbonate release a proton to ammonia, to make ammonium and carbonate anion.

Amonium cation release a proton to the hydroxide to make ammonia and water.

exis [7]3 years ago
5 0

Answer:

See explanation

Explanation:

Step 1: Data given

Bronsted-Lowry says the following:

Acid dissociation: HX + H2O → H3O+ + X-

Base dissociation: B + H2O → OH- + HB+

HC2H3O2 + H2O →

HC2HO2 is acetic acid, it's a weak acid. (CH3COOH)

This will be following the reaction HX + H2O → H3O+ + X-

CH3COOH + H2O → CH3COO- + H3O+

H2SO4 + H2O →

H2SO4 is a strong acid

This will be following the reaction HX + H2O → H3O+ + X-

H2SO4 + H2O → HSO4- + H3O+

CO3^2- + H2O →

CO3^2_ is a conjugate base

This will be following the reaction B + H2O → OH_ + HB+

CO3^2- + H2O → HCO3- + OH-

HCO3- + NH3 →

HCO3- (known as bicarbonate) is the conjugate base of H2CO3, a weak acid, and the conjugate acid of the carbonate ion.

NH3 is a weak base

HCO3- + NH3 → CO3^2- + NH4+

NH4+ + OH- →

The hydrogen on the ammonium ion (NH4+) can go back to the hydroxide ion (OH-) to form NH3 and H2O (ammonia and water) again. In this case, because the ammonium ion is donating a proton, it is called a conjugate acid.

NH4+ + OH- → NH3 + H2O

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What is that the theoretical yield of aluminum oxide I if 3.20 mol of aluminum metal is exposed to 2.70 mole of oxygen
photoshop1234 [79]

Answer:

163.2g

Explanation:

First let us generate a balanced equation for the reaction. This is shown below:

4Al + 3O2 —> 2Al2O3

From the question given, were were told that 3.2moles of aluminium was exposed to 2.7moles of oxygen. Judging by this, oxygen is excess.

From the equation,

4moles of Al produced 2moles of Al2O3.

Therefore, 3.2moles of Al will produce = (3.2x2)/4 = 1.6mol of Al2O3.

Now, let us covert 1.6mol of Al2O3 to obtain the theoretical yield. This is illustrated below:

Mole of Al2O3 = 1.6mole

Molar Mass of Al2O3 = (27x2) + (16x3) = 54 + 48 =102g/mol

Mass of Al2O3 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of Al2O3 = 1.6 x 102 = 163.2g

Therefore the theoretical of Al2O3 is 163.2g

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3 years ago
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C

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See explanation

Explanation:

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In this case, I suspect the presence of silver ions and/or barium ions. The first step is to add dilute HCl. This will lead to the precipitation of the silver ion as AgCl. If a white precipitate is formed upon addition of HCl then Ag^+ is present in the solution.

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