Answer:
Explanation:
Aluminium is used in rechargeable battery.
Aluminium ions provide the energy by flowing from anode to the cathode.
When the battery is recharged these ions comes to the anode.
The one ion gives three electrons. Which means one Al⁺³ is equal to the three Li⁺ ions. So, three unit of charge giving by ions increase the energy storage capacity.
The rechargeable batteries with aluminium gives low cost and low flammability.
It is safe to use because of inertness of aluminium and also easy to use in ambient environment.
Aluminium also have high volume capacity than lithium which means energy storage per volume is greater.
Its charge discharge cycles are also greater.
The aluminum ion batteries are also smaller in size.
Explanation:
Sodium has atomic number of 11 and its electronic configuration is given by:
![[Na]=1s^22s^22p^63s^1](https://tex.z-dn.net/?f=%5BNa%5D%3D1s%5E22s%5E22p%5E63s%5E1)
The nearest stable electronic configuration to sodium is of the neon. So, in order to attain stability of noble gas it will loose its single electron.
![[Na^+]=1s^22s^22p^63s^0](https://tex.z-dn.net/?f=%5BNa%5E%2B%5D%3D1s%5E22s%5E22p%5E63s%5E0)
Sodium has single valency that is 1.
Let nbe the valency of the ion 'X'
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
So, the formulas for all the possible compounds that sodium can form with the other ions will be:
Answer: 2.48×10^-17 J
Explanation:
Given the following :
Wavelength = 8nm (8 x 10^-9 m)
Energy(e) of X-ray =?
Energy=[speed of light(c) × planck's constant (h)] ÷ wavelength
Speed of light = 3×10^8m/s
Planck's constant = 6.626×10^-34 Js
Wavelength = 8 x 10^-9 m
Energy = [(3×10^8) * (6.626×10^-34)] / 8 x 10^-9
Energy = [19.878×10^(8-34)] / 8 x 10^-9
Energy = 2.48475 × 10^(-26+9)
Energy = 2.48×10^-17 J
Answer:
79.04 L
Explanation:
We are given;
Initial Volume; V1 = 6.24L
Initial Pressure; P1 = 760 mm Hg
Final pressure; P2 = 60.0mm Hg
To solve for final volume, we will use Boyles law;
P1•V1 = P2•V2
Let's make V2 which is the final volume the subject;
V2 = (P1•V1)/P2
V2 = (760 × 6.24)/60
V2 = 79.04 L
