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MrRa [10]
4 years ago
15

Someone please help

Mathematics
1 answer:
nordsb [41]4 years ago
4 0

Answer:

\large\boxed{6\sqrt[5]{x^2y}=6x^\frac{2}{5}y^\frac{1}{5}}

Step-by-step explanation:

\sqrt[n]{a^m}=a^\frac{m}{n}\\\\6\sqrt[5]{x^2y}=(6)(\sqrt[5]{x^2})(\sqrt[5]{y})=6x^\frac{2}{5}y^\frac{1}{5}

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Answer:

What is the missing term in the series 9, 27, 31,155, 161, 1127?

First number = 9

Second number = 9*3 = 27

Third number = 27+4 = 31

Fourth number = 31*5 = 155

Fifth number = 155+6 = 161

Sixth number = 161*7 =1127

Seventh number =1127+8 = 1135

Eighth number = 1135*9 = 10215

Ninth number = 10215+10 = 10225

Tenth number = 10225*11 =112475

Step-by-step explanation:

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