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tankabanditka [31]
4 years ago
7

Calculate LaTeX: \DeltaΔGº for a voltaic cell with Eºcell = +0.24 V if the overall reaction involves a 3 electron reduction.

Chemistry
1 answer:
umka2103 [35]4 years ago
7 0

Answer:

-69 kJ

Explanation:

Step 1: Given data

Standard cell potential (E°cell): +0.24 V

Electrons involved (n): 3 mol

Step 2: Calculate the standard Gibbs free energy change (ΔG°) for the voltaic cell

We will use the following expression.

ΔG° = -n × F × E°cell

where,

F is Faraday's constant (96,485 C/mol e⁻)

ΔG° = -n × F × E°cell

ΔG° = -3 mol e⁻ × 96,485 C/mol e⁻ × 0.24 V

ΔG° = -69 kJ

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Please help with this
GenaCL600 [577]

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6 0
3 years ago
Which marine life zones are warm, well lit, and have lots of marine life?
Ilya [14]

<u>Epipelagic </u>zones are warm, well lit, and have lots of marine life.

Explanation:

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5 0
3 years ago
At 25.0 °C the Henry's Law constant for sulfur hexafluoride (SP) gas in water is 2.4x 10 M/atm Calculate the mass in grams of SF
Dmitry_Shevchenko [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass is m =  0.0349 \ g

Explanation:

From the question we are told that

   The Henry's Law constant is  k = 2.4 *10^{10} M/atm

   The volume of water is V = 525 \ ml = 0.525 \ L

   The partial pressure is  P =  1.90 \ atm

   The temperature is T  = 25 ^oC

Henry's  law is mathematically represented as

       C  = P * k

Where C is  the concentration of sulfur hexafluoride(SP)

substituting value

        C = 1.90 * 2.4*10^{-4}

        C = 4.56*10^{-4} \ M

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        n = C * V

substituting value

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       n =  2.39 *10^{-4} \ moles

The mass of SP that dissolved is

          m = n * Z

Where Z is the molar mass of SP which has a constant value of

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So

         m =  2.394*10^{-4} * 146

         m =  0.0349 \ g

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3 years ago
3Fe+4H2O--&gt;Fe3O4+4H2 What is the mole ratioof Fe3O4 to Fe?
love history [14]
For every 3 Fe there is only 1 Fe3O4 producing.
So, ratio would be: Fe3O4 / Fe = 1 / 3

In short, Your Answer would be: 1 : 3

Hope this helps!
6 0
3 years ago
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