An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally through a distance of 6.00 m. What
1 answer:
Answer:
The answer to the question is
The change in the kinetic energy of the object is 600 J
Explanation:
The known variables are,
Mass of object, m = 100 kg
Force of object, F = 100 N
The relation for kinetic energy = KE = = 0.5·m·v²
Therefore to find v we first find the acceleration from
F = m·a =10.0 kg × a = 100 N,
Where a = acceleration of the object =100/10 = 10 m/s²
To find the velocity, v, we use the relationship
v² = u² + 2 × a × S, where S is the distance of motion = 6.00 m and u is the initial velocity, u = 0 m/s, therefore
v² = 0 + 2 × 10 m/s² × 6 m = 120 m²/s² or v = 10.95 m/s
Therefore KE = 0.5 × 10 kg × (10.95 m/s)² = 600 J
where the initial velocity, u = 0 m/s
Initial kinetic energy of the object = KE₁ = 0.5 × 10 × 0² = 0
The change in kinetic energy of the object = 600 J - 0 J = 600 J
You might be interested in