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Anika [276]
3 years ago
14

Calculate the standard cell potential at 25 ∘C for the reaction X(s)+2Y+(aq)→X2+(aq)+2Y(s) where ΔH∘ = -687 kJ and ΔS∘ = -169 J/

K .
express your answer to three significant figures and include the appropriate

Chemistry
1 answer:
aivan3 [116]3 years ago
6 0

Answer:

-0.129V

Explanation:

The change in free energy is obtained from the given parameters after which the value is now applied to obtain the cell potential in volts from the formukar shown in the solution below.

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What is the formula used to calculate the heat required to warm or cool one phase of matter
Ronch [10]

Answer:

SPECIFIC HEAT CAPACITY

Explanation:

Q = MC DELTA T

q = heat

c = specific heat

T = temperature ( final - initial )

4 0
3 years ago
1. Explain the two processes that keep atmospheric oxygen and carbon dioxide at stable levels?
lesya [120]

Cellular Respiration and Photosynthesis. Photosynthesis is the process of when plants use sunlight to make foods from carbon dioxide and water, to later on make oxygen. Cellular respiration is the process through which cells convert sugars into energy.

4 0
3 years ago
We can also perform a similar calculation for the mass defect and binding energy for nuclear reactions using the masses of the a
sukhopar [10]

Answer:

See Explanation

Explanation:

\frac{235}{92} U + \frac{1}{0} n ---->\frac{137}{52} Te + \frac{97}{40} Zr +2\frac{1}{0} n

Hence the mass defect is;

[235.04393 + 1.00867] - [ 136.92532 + 96.91095 + 2(1.00867)]

=  236.0526 - 235.85361

= 0.19899 amu

Since 1 amu = 1.66 * 10^-27 Kg

0.19899 amu = 0.19899 * 1.66 * 10^-27 = 3.3 * 10^-28 Kg

Binding energy = Δmc^2

Binding energy = 3.3 * 10^-28 Kg * (3 * 10^8)^2 = 2.97 * 10^-11 J

ii) \frac{10}{5}B + \frac{1}{0}n-----> \frac{7}{3} Li + \frac{4}{2} He + Energy

Hence the mass defect is;

[10.01294 + 1.00867] - [7.01600 + 4.00260]

= 11.02161 - 11.0186

= 0.00301 amu

Since 1 amu = 1.66 * 10^-27 Kg

0.00301 amu = 0.00301 * 1.66 * 10^-27 = 4.997 * 10^-30 Kg

Binding energy = Δmc^2

Binding energy = 4.997 * 10^-30 Kg * (3 * 10^8)^2 = 4.5 * 10^-13 J

7 0
2 years ago
Basic substances have a gritty texture.
crimeas [40]
<h3>1.<u> Answer;</u></h3>

False

<h3><u>Explanation;</u></h3>

Bases have some of the following properties;

  • They have a bitter taste
  • They have a slimy, or soapy feel on fingers
  • Most bases react with acids and precipitate salts.
  • Strong bases may react violently with acids.
  • Bases turn red litmus paper blue

<h3>2. <u>Answer;</u></h3>

An acid

<h3><u>Explanation;</u></h3>
  • When acids are dissolved in water, the concentration of the acid decreases and it becomes dilute.
  • It dissociates in water to give H+ ions or hydrogen ions.
  • All acidic solutions contain more hydrogen ions than hydroxide ions, therefore when added to water it increases the concentration of H+ ions in water, as water is a neutral substance whose concentration of H+ ions is equal to OH-.
5 0
3 years ago
Homes in rural areas where natural gas service is not available often rely on propane to fuel kitchen ranges. The propane is sto
Neporo4naja [7]

Answer:

2666.7 hours

Explanation:

The key to solve this problem is that we are given the propane gas consumed in one hour by giving us the information of the volume consumed at 1 atm, 298 K (25 +273). Using the gas law we can calculate the rate of consumption  of propane per hour, and from here we can calculate its mass and converting it to gallons and finally diving the 400 gallos by this number.

PV = nRT ∴ n = PV/RT

n = 1 atm x 165 L/ (0.08206 Latm/kmol x 298 K ) = 6.75 mol propane

Mass propane :

6.75 mol x 44 g/mol = 296.88 g

convert this to Kg:

296.88 g/ 1000 g/Kg = 0.30 Kg

calculate the volume in liters this represents by dividing by the density:

0.30 Kg / 0.5077 Kg/L =  0.59 L

changing this to gallons

0.59 L x  1 gallon/3.785 L = 0.15 gallon

and finally calculate how many hours the 400 gallons propane tank will deliver

400 gallon/ 0.15 gallon/hr = 2666.7 hr

6 0
3 years ago
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