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Scilla [17]
2 years ago
6

Assume sin t =.45 and sin w =.89 both t and w are postive and both t and w determne a terminal point in a quadrant 1. which of t

he following statements best describe the relationship between t and w
a w>t
b t>w
C not possible to tell
Mathematics
2 answers:
stich3 [128]2 years ago
6 0

Answer:

Option a - w>t

Step-by-step explanation:

Given : sin t =0.45 and sin w =0.89 both t and w are positive and both t and w determine a terminal point in a quadrant 1.

To find : Which of the following statements best describe the relationship between t and w?

Solution :

First quadrant implies the  angle with the x-axis is between 0 and 90 degrees.

In the first quadrant, the sine function INCREASES from 0 to 1.

sin(0) = 0,

sin(90) = 1

So, sin(w)=0.89 > sin(t)=0.45

Since sin(w) > sin(t),

w > t in the first quadrant.

Therefore, Option a is correct .

Sidana [21]2 years ago
5 0
The sine function is increasing in the first quadrant.
sin(0) = 0
sin(90) = 1

This means the larger angle will give a larger sine value.
sin(w) > sin(t) -----> w > t
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What angle do the minute and hour hands make at 4:30??
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3 0
3 years ago
Emily and Sarah had a total of $80. after Sarah spent 1/3 of her money and Emily spent $17, Emily had twice as much money as Sar
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3 0
2 years ago
The scale on a map is 1: 75 000. (a) Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.
finlep [7]

Answer:

a. 1 200 000 km

b. 0.000 773 cm

c. 67 500 000 000 km²

d. 0.000 000 016 cm²

Step-by-step explanation:

a. Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

So, 1 cm : 75000 km = 16 cm : x km

So, 1 cm/75000 km = 16 cm/x km

Thus x km = 16 cm × 75000 km/1 cm = 1 200 000 km

(b) Calculate length of a road on the map which is 0.58 km.

Let y be the length of road on the map. So, using our scale

1 cm : 75000 km = y cm : 0.58 km

So, 1 cm/75000 km = y cm/0.58 km

Thus y cm = 0.58 km × 1 cm/75000 km = 0.000 773 cm

(c) Calculate, in km², the ACTUAL area of a lake which is 12 cm2 on the map.

Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

Let z be the actual area of the lake.

So,  1 cm² : 5 625 000 000 km² = 12 cm² : z km²

So, 1 cm²/5 625 000 000 km² = 12 cm²/z km²

Thus z km² = 12 cm² × 5 625 000 000 km²/1 cm² = 67 500 000 000 km²

(d) Calculate the area of a play field on the map which has has an actual area of 90 km².

Let a represent the area of the play field on the map. Using our scale for the area,

1 cm² : 5 625 000 000 km² = a cm² : 90 km²

So, a cm² = 90 km² × 1/5 625 000 000 km² = 0.000 000 016 cm²

4 0
2 years ago
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