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Dominik [7]
3 years ago
5

Marcos had 15 coins in nickels and quarters. He had 3 more quarters than nickels. He wrote a system of equations to represent th

is situation, letting x represent the number of nickels and y represent the number of quarters. Then he solved the system by graphing. What is the solution?
Mathematics
1 answer:
Gwar [14]3 years ago
8 0

Answer:

6 nickels and 9 quarters

Step-by-step explanation:

x- nickels

y- quarters

----------------

the 2 equations are:

  • x+y=15
  • y-x= 3

add up the 2 equations:

  • 2y= 18
  • y=9

then

  • x= 15-9
  • x=6
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I don't know how to work this problem out
madam [21]
1/5(x-y) = 1
x+y = 9

x-y = 5 (x5)
x+y = 9

First you want to create both equations so at least one of the variables (x or y) are the same in both equations, so that is why I multiplied the top one by 5, you multiply the whole equation (both sides)

2x = 14
x = 7

Then you either Plus or minus one from the other, I plused the top one onto the bottom one, then solved for x

7 + y = 9
y = 2

Then put x back into one of the first two equations to get Y


4 0
3 years ago
Geometry question, need help.
Margaret [11]
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3 years ago
15y^2-15y+2y+7-2y^2+4
scoray [572]

Answer:

13 y^2 - 13 y + 11

Step-by-step explanation:

Simplify the following:

15 y^2 - 2 y^2 + 2 y - 15 y + 4 + 7

Grouping like terms, 15 y^2 - 2 y^2 + 2 y - 15 y + 4 + 7 = (15 y^2 - 2 y^2) + (-15 y + 2 y) + (7 + 4):

(15 y^2 - 2 y^2) + (-15 y + 2 y) + (7 + 4)

15 y^2 - 2 y^2 = 13 y^2:

13 y^2 + (-15 y + 2 y) + (7 + 4)

2 y - 15 y = -13 y:

13 y^2 + -13 y + (7 + 4)

7 + 4 = 11:

Answer: 13 y^2 - 13 y + 11

8 0
3 years ago
Assume that y varies directly with x. If x = -4 when y = -8, find y when x = 6.
astra-53 [7]
-4/-8  6/x
y=12

the answer is y=12 when x=6
8 0
3 years ago
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tamaranim1 [39]

Answer: 3 losses

Step-by-step explanation: The win to loss ratio is 4:1. Their losses are 1/4 of their wins. Multiply 12, their number of wins, by 1/4.

12 x 1/4 = 3

They have lost 3 games.

3 0
3 years ago
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