Answer:
a place where someone or something is located or has been put.
Answer:
The car would travel after applying brakes is, d = 14.53 m
Explanation:
Given that,
The time taken to apply brakes fully is, t = 0.5 s
The velocity of the car, v = 29.06 m/s
The distance traveled by the car in 0.5 s, d = ?
The relation between the velocity, displacement, and time is given by the formula
d = v x t m
Substituting the values in the above equation,
d = 29.06 m/s x 0.5 s
= 14.53 m
Therefore, the car would travel after applying brakes is, d = 14.53 m
We have that the the scenarios the flux is behavior is as follows:
- Here The -ve charge placed outside the surface will not affect the total flux charge.
- We have that the flux remains constant.
- Here with the <em>negative </em>charge outside, the flux will decrease.
- This will not affect net flux change, whereas if it where inside.It will increase flux.
Generally for each change
A positive charge is placed just inside the surface:
Here The -ve Charge placed outside the surface will not affect the total flux charge.
The charge is moved of-center by an amount equal to half the radius of the spherical surface.
We have that the flux remains constant.
A negative charge is placed just outside the surface.
Here with the <em>negative </em>charge outside, the flux will decrease.
A <u>positive </u><em>charge </em>is placed just outside the surface.
This will not affect net flux change, whereas if it where inside.It will increase flux.
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Complete Question
A positive point charge is placed at the center of an imaginary spherical surface. As a result, there is some total electric flux outward through the surface. For each change listed, how would the total outward flux though the surface change?.
- A positive charge is placed just inside the surface .
- The charge is moved of-center by an amount equal to half the radius of the spherical surface .
- A negative charge is placed just outside the surface.
- A positive charge is placed just outside the surface.