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Vladimir79 [104]
2 years ago
10

Determine the inductive reactance for a 50 mH inductor that is across a 15 volt, 400 Hz source.

Physics
1 answer:
tresset_1 [31]2 years ago
8 0

Answer:

Inductive reactance is 125.7 Ω

Explanation:

It is given that,

Inductance, L=50\ mH=0.05\ H

Voltage source, V = 15 volt

Frequency, f = 400 Hz

The inductive reactance of the circuit is equivalent to the impedance. It opposes the flow of electric current throughout the circuit. It is given by :

X_L=2\pi fL

X_L=2\pi \times 400\ Hz\times 0.05\ H

X_L=125.66\ \Omega

X_L=125.7\ \Omega

So, the inductive reactance is 125.7 Ω. Hence, this is the required solution.

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The initial force between the two charges is given by:

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So, the new force is:

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In this case, q1 and q2 are unchanged. The distance between the charges is doubled to 2d.

So, we have:

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3. 6F

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Answer:

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Greetings !

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