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3 years ago

Determine the inductive reactance for a 50 mH inductor that is across a 15 volt, 400 Hz source.

Physics

1 answer:

tresset_1 [31]3 years ago

8 0

Answer:

Inductive reactance is 125.7 Ω

Explanation:

It is given that,

Inductance, $L=50\ mH=0.05\ H$

Voltage source, V = 15 volt

Frequency, f = 400 Hz

The inductive reactance of the circuit is equivalent to the impedance. It opposes the flow of electric current throughout the circuit. It is given by :

$X_L=2\pi fL$

$X_L=2\pi \times 400\ Hz\times 0.05\ H$

$X_L=125.66\ \Omega$

$X_L=125.7\ \Omega$

So, the inductive reactance is 125.7 Ω. Hence, this is the required solution.

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7nadin3 [17]

Answer:

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4 0

3 years ago

A golf ball (mass 0.045 kg) is hit with a club from a tee. The plot shows the force on the ball as a function of time in millise

almond37 [142]

Answer:

16.3 m/s

Explanation:

We are given that

Mass of golf ball=m=0.045 kg

We have to find the speed right after the hit.

$b_1=(16-1)\times 10^{-3}=15\times 10^{-3} s$

$b_2=(12-6)\times 10^{-3}=6\times 10^{-3} s$

Force,F=70 N

Change in momentum=Area of trapezium

Area of trapezium,A= $\frac{1}{2}(b_1+b_2) h$

Using the formula

$m(v-u)=\frac{1}{2}(15+6)\times 10^{-3}\times 70$

$0.045(v-u)=\frac{1}{2}(21)\times 10^{-3}\times 70$

$v-u=\frac{1}{2}\times \frac{1}{0.045}\times 21\times 10^{-3}\times 70$

$v-u=16.3$

Initial velocity of golf ball=u=0

$v-0=16.3$

$v=16.3 m/s$

5 0

3 years ago

The diagram below shows a wave with its wavelength indicated in red.

lisabon 2012 [21]

C. It will decrease

5 0

4 years ago

Read 2 more answers

Calculate the displacement of the volleyball in sample problem 2f when teh volleyballs final velocity is 1.1 m/s upward

stich3 [128]

We have: v i (initial velocity) = 6 m/sv = 1.1 m/sa = - 9.8 m/s²v = v i + a · t1.1 m/s = 6 m/s - 9.8 m/s² t9.8 t = 6 - 1.19.8 t = 4.9t = 4.9 : 9.8t = 0.5 sThen the replacement:x = xi + vi · t + a t² / 2( xi = 0 )x = 6 · 0.5 - 9.8 · 0.25 / 2x = 3 - 1.225Answer:
x = 1.775 m

4 0

4 years ago

The pressure exerted by a gas is 2.0 atm while it has a volume of 350 mL. What would be the volume of this sample of gas at stan

34kurt

Answer:

700 mL or 0.0007 m³

Explanation:

P₁ = Initial pressure = 2 atm

V₁ = Initial volume = 350 mL

P₂ = Final pressure = 1 atm

V₂ = Final volume

Here the temperature remains constant. So, Boyle's law can be applied here.

P₁V₁ = P₂V₂

$\frac{P_1V_1}{P_2}=V_2\\\Rightarrow V_2=\frac{2\times 350}{1}\\\Rightarrow V_2=700\ mL$

So, volume of this sample of gas at standard atmospheric pressure would be 700 mL or 0.0007 m³

7 0

4 years ago