Question

If a box weighing 520 N is hung from a spring whose constant is 650 N/m, how many centimeters will the spring stretch?

Answer 1

Answer:

x= 80 cm : Spring stretch

Explanation:

Hooke's law:

The force applied to a spring is proportional to the spring stretching:

F=K*x (Formula (1)

Where:

F=Force applied to the spring (N)

K= spring elasticity constant (N/m)

x= spring stretch (m)

Known data

F=520 N

k=650 N/m

Problem development

We apply formula (1) for calculate the spring strech (x):

F=K*x

520N=(650 N/m) *x

x= (520N) / (650 N/m)

x= 0.8 m = 0.8m* 100cm/m = 80cm

x= 80 cm

Answer 2

80 cm

hope this helps :)