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2 years ago

PLEASE HURRY!!!

Physics

2 answers:

kow [346]2 years ago

7 0

Answer:

Explanation:

The bottom of the mountain is not correct because your trying to stop.

The top is of the mountain is when you gain energy.

The middle is when you have the most kinectic energy.

beks73 [17]2 years ago

3 0

D because because that has the most potential energy

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Can a object have have zero velocity and nonzero acceleration?

vladimir1956 [14]

Answer:

yes

Explanation:

3 0

2 years ago

A parallel-plate capacitor with circular plates of radius R is being charged by a battery, which provides a constant current. At

NikAS [45]

To solve this problem it is necessary to apply the concepts related to the magnetic field.

According to the information, the magnetic field INSIDE the plates is,

$B=\frac{1}{2} \mu \epsilon_0 r$

Where,

$\mu =$ Permeability constant

$\epsilon_0 =$ Electromotive force

r = Radius

From this deduction we can verify that the distance is proportional to the field

$B \propto r$

Then the distance relationship would be given by

$\frac{r}{R} = \frac{B}{B_{max}}$

$r =\frac{B}{B_{max}} R$

$r = \frac{0.5B_{max}}{B_{max}}R$

$r = 0.5R$

On the outside, however, it is defined by

$B = \frac{\mu_0 i_d}{2\pi r}$

Here the magnetic field is inversely proportional to the distance, that is

$B \not\propto r$

Then,

$\frac{r}{R} = \frac{B_{max}{B}}$

$r = \frac{B_{max}{B}}R$

$r = \frac{B_{max}{0.5B_{max}}}R$

$r = 2R$

7 0

2 years ago

A girl drops a stone from the top a tower 45m tall. At the same time, a boy standing at the base of the tower, projects another

Advocard [28]

Answer:

(i) The stones meet at 1.8 second

(ii) The point at which the stones meet, is 28.8 m above the base of the building and 16.2 m below the top of the building.

Explanation:

(i)

First we consider the stone dropped by the girl. We have data:

Vi = Initial Velocity of Stone = 0 m/s (Since the stone was initially at rest)

t = Time Period

g = 10 m/s²

s₁ = Distance Covered by Stone

Using 2nd equation of motion, we get:

s₁ = Vi t + (0.5)gt²

s₁ = (0)(t) + (0.5)(10)t²

s₁ = 5t² ----- equation (1)

Now, we consider the stone throne vertically upward by the boy. We have data:

Vi = Initial Velocity of Stone = 25 m/s

t = Time Period

g = - 10 m/s² (negative sign due to upward motion)

s₂ = Distance Covered by Stone

Using 2nd equation of motion, we get:

s₂ = Vi t + (0.5)gt²

s₂ = (25)(t) + (0.5)(-10)t²

s₂ = 25t - 5t² ----- equation (2)

At, the point where both the stones meet, the sum of distances covered by both stones must be equal to the height of building (i.e 45 m).

s₁ + s₂ = 45

using values from equation (1) and equation (2)

5t² + 25t - 5t² = 45

25t = 45

t = 45/25

t = 1.8 sec

(ii)

using this value of of t in equation (2)

s₂ = (25)(1.8) - (5)(1.8)²

s₂ = 28.8 m

using this value of of t in equation (1)

s₁ = (5)(1.8)²

s₁ = 16.2 m

Hence, the point at which the stones meet, is 28.8 m above the base of the building and 16.2 m below the top of the building.

6 0

3 years ago

As you lift an 88 N box straight upward you produce a power of 72 W. What is the speed of the box?

jeka57 [31]

F = force applied to lift the box = weight of the box = 88 N

P = power produced while lifting the box upward = 72 Watt

v = speed of the box = ?

Speed of the box is given as

v = $\frac{P}{F}$

inserting the values

v = $\frac{72}{88}$

v = 0.82 ms⁻¹

6 0

2 years ago

Read 2 more answers

Calcula la energía cinética de un coche de 500kg de masa que se mueve a la velocidad de 100 km/h. Pasamos la velocidad a las uni

castortr0y [4]

Responder:

192,900.64 Julios

Explicación:

La energía cinética es la energía que posee un cuerpo en virtud de su movimiento. Sea la masa del cuerpo m, su velocidad v.

Energía cinética = 1/2 mv²

Parámetros dados

masa del coche = 500 kg

velocidad = 100 km / h

La velocidad debe estar en m / s según la unidad internacional estándar. Al convertir;

100 km / h = 100 * 1000/3600 m / s

100 km / h = 27,8 m / s

velocidad del cuerpo = 27,8 m / s

Necesario

Energía cinética del coche = 1/2 * 500 * 27,8²

Energía cinética del automóvil = 1/2 * 500 * 771.6

Energía cinética del automóvil = 1/2 * 385,801.28

Energía cinética del automóvil = 192,900.64 Julios

Por lo tanto, la energía cinética del automóvil es 192,900.64 julios.

5 0

3 years ago