1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DiKsa [7]
3 years ago
6

What is the average velocity of the particle from rest to 9 seconds?

Physics
1 answer:
geniusboy [140]3 years ago
7 0
Answer: v = 2[m/s]Explanation:This avarage velocity can be found with the ... B. 2 meters/ second. C. 3 meters/second. D. 4 meters/second. 1.
You might be interested in
1:A pattern or grouping of stars that people imagine representing a figure, an animal or an object.
Nesterboy [21]

Answer:

  • 1.constellation
  • 2.Probably a dwarf planet
7 0
3 years ago
The name of the Sl unit for force is the ___?<br><br> A. Joule<br> B. Newton<br> C.Watt
tiny-mole [99]

Answer:

the name of the SI unit for force is the newton

8 0
3 years ago
Read 2 more answers
A source emits sound uniformly in all directions. There are no reflections of the sound. At a distance of 12 m from the source,
yaroslaw [1]

Answer:

1.58 W

Explanation:

Since the sound spreads uniformly in all directions, it must be in a form of a circle with radius of 12 m. So the area of the circle is

A = \pi r^2 = \pi 12^2 = 452.389 m^2

From the intensity of the sound we can calculate the power at 12 m

P = AI = 452.389 * 3.5\times10^{-3} = 1.58 W

7 0
3 years ago
Two tiny particles having charges of +5.00 μC and +7.00 μC are placed along the x-axis. The +5.00-µC particle is at x = 0.00 cm,
Liula [17]

Answer:

The third charged particle must be placed at x = 0.458 m = 45.8 cm

Explanation:

To solve this problem we apply Coulomb's law:  

Two point charges (q₁, q₂) separated by a distance (d) exert a mutual force (F) whose magnitude is determined by the following formula:  

F = \frac{k*q_1*q_2}{d^2} Formula (1)  

F: Electric force in Newtons (N)

K : Coulomb constant in N*m²/C²

q₁, q₂: Charges in Coulombs (C)  

d: distance between the charges in meters (m)

Equivalence  

1μC= 10⁻⁶C

1m = 100 cm

Data

K = 8.99 * 10⁹ N*m²/C²

q₁ = +5.00 μC = +5.00 * 10⁻⁶ C

q₂= +7.00 μC = +7.00 * 10⁻⁶ C

d₁ = x (m)

d₂ = 1-x (m)

Problem development

Look at the attached graphic.

We assume a positive charge q₃ so F₁₃ and F₂₃ are repulsive forces and must be equal so that the net force is zero:

We use formula (1) to calculate the forces F₁₃ and F₂₃

F_{13} = \frac{k*q_1*q_3}{d_1^2}

F_{23} = \frac{k*q_2*q_3}{d_2^2}

F₁₃ = F₂₃

\frac{k*q_1*q_3}{d_1^2} = \frac{k*q_2*q_3}{d_2^2} We eliminate k and q₃ on both sides

\frac{q_1}{d_1^2}= \frac{q_2}{d_2^2}

\frac{q_1}{x^2}=\frac{q_2}{(1-x)^2}

\frac{5*10^{-6}}{x^2}=\frac{7*10^{-6}}{(1-x)^2} We eliminate 10⁻⁶ on both sides

(1-x)^2 = \frac{7}{5} x^2

1-2x+x^2=\frac{7}{5} x^2

5-10x+5x^2=7 x^2

2x^2+10x-5=0

We solve the quadratic equation:

x_1 = \frac{-b+\sqrt{b^2-4ac} }{2a} = \frac{-10+\sqrt{10^2-4*2*(-5)} }{2*2} = 0.458m

x_2 = \frac{-b-\sqrt{b^2-4ac} }{2a} = \frac{-10-\sqrt{10^2-4*2*(-5)} }{2*2} = -5.458m

In the option x₂, F₁₃ and F₂₃ will go in the same direction and will not be canceled, therefore we take x₁ as the correct option since at that point the forces are in  opposite way .

x = 0.458m = 45.8cm

8 0
3 years ago
Which force is responsible for allowing carbon-14 to become stable? *
Bas_tet [7]

Answer:weak nuclear

Explanation:

There weak nuclear force is responsible for allowing carbon-14 to become stable

3 0
3 years ago
Other questions:
  • Compare and contrast rutherford's "planetary model" of the atom with our current understanding of an atom's internal structure.
    5·1 answer
  • help plz
    5·1 answer
  • A heavy boy and a lightweight girl are balanced on a massless seesaw. The boy moves backward, increasing his distance from the p
    6·1 answer
  • hot-air balloon is ascending at the rate of 14 m/s and is 84 m above the ground when a package is dropped over the side. (a) How
    8·2 answers
  • Give me as many as possible benefits for the neck stretch.
    5·1 answer
  • A 675 kg car moving at 15.7 m/s hits from behind another car moving at 9.6 m/s in the same direction. If the second car has a ma
    15·1 answer
  • 5. A ball weighing 10 kg rolls 200 m down a frictionless incline with a 50 degree angle to the horizontal. If the ball’s initial
    6·1 answer
  • Velocity v (m/s)
    12·1 answer
  • Perform the following mathematical operation and report the answer to the correct number of significant figures 143.6/21.2
    12·1 answer
  • Name:
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!