This is a combination problem.
Given:
12 students
3 groups consisting of 4 students.
Mark can't be in the first group.
The combination formula that I used is: n! / r!(n-r)!
where: n = number of choices ; r = number of people to be chosen.
This is the formula I used because the order is not important and repetition is not allowed.
Since Mark can't be considered in the first group, the value of n would be 11 instead of 12. value of r is 4.
numerator: n! = 11! = 39,916,800
denominator: r!(n-r)! = 4!(11-4)! = 4!*7! = 120,960
Combination = 39,916,800 / 120,960 = 330
There are 330 ways that the instructor can choose 4 students for the first group
Answer:
C. 75 restaurant customers
Step-by-step explanation:
With the way the graph is laid out 75 restaurant customers seems to be the most logical answer.
<em>So the parallelogram Formula is B×H</em>
<em>Plug in </em>
<em>12 3\4 ×1\2</em>
<em>51\4 × 1\2 </em>
<em>51\8 = 6.375</em>
<em>So if you solve you will be gated 6.375 </em>
Answer:
(C) (4,0)
Step-by-step explanation:
Given the graph which represents the system of equations:
3x+4y=12; and
2x-y=8.
- One line passes through (0, 3) and (4, 0).
- The other line passes through (2, -4) and (4, 0).
From the points given, both lines pass through the point (4,0).
Therefore, the ordered pair which is a solution to the system of equations is (4,0).
The correct option is C.
Answer:
144
Step-by-step explanation:
First subtract 180 from 20% of 180.
180 - (20/100 x 180) = 180-36 = 144
